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Vsevolod [243]
2 years ago
6

Classify the following triangle.

Mathematics
1 answer:
Pani-rosa [81]2 years ago
4 0

Answer:

A. Scalene

E. Obtuse

Step-by-step explanation:

Obtuse are angles that are greater than 90°

Scalene is not congruent sides.

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Convert 6 and 3/5 to an improper fraction.
VikaD [51]

Answer: 33/5

Step-by-step explanation:

6 x 5 = 30

30 + 3 = 33

7 0
4 years ago
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Help me please. either one is fine.
mestny [16]
7)
95+(3x+23)+(7x-4)+(9x-6)+90 = (5-2) x 180
x = 18

9)
41+(3x+6)+(7x-11)+62+(4x+7)+(6x-5) = 360
x = 13


6 0
3 years ago
Shawna has four gumdrops that are blue, red, yellow, and green. She randomly picks one gumdrop from a bag and replaces it.
marshall27 [118]
The answers are as follows; .275,.225, 2, .30
5 0
3 years ago
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144 students enter a spelling bee, but only 1/6 of the group will make into the semi-final round, and only 2 /3​ that group will
DerKrebs [107]

Answer:

16 students

Step-by-step explanation:

144 students enter a spelling bee contest.

Step 1

For the semi final round we are told that only 1/6 of the group will make it into that round.

This is calculated as

1/6 × 144/students = 24 students.

This means that only 24 students would make it into the semi final rounds.

Step 2

We are also told in the question that only 2/3 of THAT group would make it into the final round.

" THAT" group been referred to in the question means the number students that made it to the semi final round

This is calculated as

2/3 of that group( the group that made it to the semi finals)

= 2/3 × 24 students

= 16 students.

Therefore, the number of students that will enter the final round of the spelling bee is 16 students.

6 0
3 years ago
Factor completely.<br> 150m^2nz+20mn^2c-120m^2nc-25mn^2z
Anika [276]

Answer:

The factor form is:

5mn\left(6m-n\right)\left(5z-4c\right)

Step-by-step explanation:

Here we have to find the factor of the expression:

150m^2nz+20mn^2c-120m^2nc-25mn^2z

So we need to take out the common terms, as we do for finding the greatest common factors.

Now the expression that is given can be re-written as:

150m^2nz+20mn^2c-120m^2nc-25mn^2z\\=150mmnz+20mnnc-120mmnc-25mnnz\\=30\cdot \:5nmmz+4\cdot \:5nmnc-24\cdot \:5nmmc-5\cdot \:5nmnz

Next, we will find the common terms, as follows;

30\cdot \:5nmmz+4\cdot \:5nmnc-24\cdot \:5nmmc-5\cdot \:5nmnz\\=5nm\left(30mz+4nc-24mc-5nz\right)\\

Now  we will factorise the expression:

\left(30mz+4nc-24mc-5nz\right)\\

as follows;

\left(30mz+4nc-24mc-5nz\right)\\=6m\left(5z-4c\right)+n\left(4c-5z\right)\\=\left(-4c+5z\right)\left(6m-n\right)\\

So the final factor form is:

150m^2nz+20mn^2c-120m^2nc-25mn^2z=5mn\left(6m-n\right)\left(5z-4c\right)

8 0
3 years ago
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