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tankabanditka [31]
3 years ago
8

Andrew writes the algrebraic expression 2s + 2.97 to represent the cost of his lunch. He bought 2 sandwhiches and a large drink.

Identify any variables, coefficients, and terms in the expression. Tell what each represents
Mathematics
1 answer:
krok68 [10]3 years ago
3 0

Answer:

Step-by-step explanation:

2s + 2.97, if he buys 2 sandwiches and a large drink then

2 represent the coefficients of s which is the number of sandwiches he bought

s represent a variable since it a function of the coefficient; s represent the price of sandwich

2.97 represent the price of large drink and also a constant since it has no letter added to  

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Dennis, Emily, and Fernando want to find the zeros of the polynomial p(x)=x3+6x2+9x. Each student worked independently and prese
alexandr402 [8]

Answer:

  • Fernando’s response is incorrect because he inappropriately applied the Rational Root Theorem.
  • Dennis’ response is incorrect. According to the Fundamental Theorem of Algebra, the polynomial p(x) cannot have six roots, or zeros, because it is only of degree 3.
  • Emily’s response is correct because she correctly factored the polynomial, and correctly used the definition of zeros to reach her answer.

Step-by-step explanation:

The Rational Root Theorem offers a list of possible rational roots. Each needs to be tested to see if it is an actual rational root. Fernando and Dennis made inappropriate assumptions about what the Rational Root Theorem allowed them to conclude.

3 0
3 years ago
PLEASE HELP!!
erik [133]
2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha

1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}

3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x
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3 years ago
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miss Akunina [59]

Answer:55

Step-by-step explanation:

sike i lied that is so easy just try

5 0
3 years ago
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GEOMETRY HELPP 15 POINTS - PICTURE INCLUDED
Gnom [1K]
Side GF^2 = 144 -100
Side GF^2 = 44
Side GF = 2*sqrt(11)
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4 0
3 years ago
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Noah tried to prove that cos(θ)=sin(θ) using the following diagram. His proof is not correct.
alukav5142 [94]

Answer:

The first statement is incorrect. They have to be complementary.

Step-by-step explanation:

You can't say the measure of angle B is congruent to theta because it is possible for angles in a right triangle to be different.

You can only say that what he said is true if the angle was 45 degrees, but based on the information provided it is not possible to figure that out.

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3 years ago
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