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1 answer:
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Given:
In the given figure the vertices of triangle ABC are A(-2,2), B(4,2), C(-2,-2).
The vertices of triangle A'B'C' are A'(-4,4), B'(8,4), C'(-4,-4).
To find:
The center of dilation and the scale factor.
Solution:
In the given graph, draw the lines AA', BB' and CC'. The intersection point of these lines is the center of dilation.
From the below graph, it is clear that the lines AA', BB' and CC' intersect each other at (0,0).
Therefore, the center of dilation is (0,0).
If a figure is dilated by factor k and the center of dilation is origin, then
It is given that A'(-4,4). So,
On comparing both sides, we get
Therefore, the scale factor is 2.
Answer:
Step-by-step explanation:
← Equation 1
By simplifying the above equation we get,
(Simplifying the brackets)
(By subtracting
from
) ← Equation 2
Multiply Equation 1 by 5 and Equation 2 by 3 and add them together.
Equation 1 multiplied by 5 will give,
Equation 2 multiplied by 3 will give,
Add those together,
(After simplifying
values)
Therefor
By substituting to Equation 1 we get,
Therefor we can say,