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Masja [62]
2 years ago
8

The Johnsons’ new swimming pool measures 3x^2-2x+1 ft in length and x+2 ft in width. What is the area of the new swimming pool,

in square feet?
Mathematics
1 answer:
Usimov [2.4K]2 years ago
8 0

Answer:

3x^3 + 4x^2 -3x + 2

Step-by-step explanation:

The area of the swimming pool will be equal to length * width.

We know that the length is 3x^2-2x+1 and the width is x+2.

Therefore we can substitute those into the equation:

(3x^2-2x+1)(x+2)\\

Then, we expand the brackets using a grid (attached).

After this, we collect like terms to find the final answer:

3x^3+6x^2-2x^2-4x+x+2\\3x^3 + 4x^2 -3x + 2

Our final answer is: 3x^3 + 4x^2 -3x + 2

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        y = x² - 4x + 8
4x + y = 12

                 4x + y = 12
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                        x = ±2
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