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Masja [62]
2 years ago
8

The Johnsons’ new swimming pool measures 3x^2-2x+1 ft in length and x+2 ft in width. What is the area of the new swimming pool,

in square feet?
Mathematics
1 answer:
Usimov [2.4K]2 years ago
8 0

Answer:

3x^3 + 4x^2 -3x + 2

Step-by-step explanation:

The area of the swimming pool will be equal to length * width.

We know that the length is 3x^2-2x+1 and the width is x+2.

Therefore we can substitute those into the equation:

(3x^2-2x+1)(x+2)\\

Then, we expand the brackets using a grid (attached).

After this, we collect like terms to find the final answer:

3x^3+6x^2-2x^2-4x+x+2\\3x^3 + 4x^2 -3x + 2

Our final answer is: 3x^3 + 4x^2 -3x + 2

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In a survey, of the voters support a particular referendum. If 40 voters are chosen at random, find the mean and variance for th
Katyanochek1 [597]

This question is incomplete, the complete question is;

In a survey, 55% of the voters support a particular referendum. If 40 voters are chosen at random,

find the mean and variance for the number of voters who support the referendum.

Answer:

a) The Mean is 22

b) Variance is 9.9

Step-by-step explanation:

Given that;

55% of the voters support a particular referendum p = 0.55

q = 1 - p = 1 - 0.55 = 0.45

sample size n = 40

a)

Mean = sample size n × p

Mean = 40 × 0.55

Mean = 22

Therefore the Mean is 22

b)

Variance = n × p × q

so we substitute

Variance = 40 × 0.55 × 0.45

Variance = 9.9

Therefore the Variance is 9.9

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