Missing data:
Viewer's Age Group Excellent Good Average Poor Marginal Total
16–25 52 42 12 7 113
26–35 33 50 5 9 97
36–45 58 12 28 34 132
46–55 25 17 22 12 76
56 + 12 5 3 8 28
Marginal Total 180 126 70 70 446
A rating of good or excellent indicates the audience liked the movie, while a rating of poor indicates the audience disliked the movie.
<h3>How to determine the rating of the film from the 46–55 age group?</h3>
A movie producer accomplished a survey behind a preview screening of her latest movie to estimate how the film would be accepted by viewers from various age groups. The table displays the numbers of viewers in various age groups who ranked the film excellent, good, average, and poor.
25/446 = 0.05605
0.05605 
100% = 5.605%
Out of the entire respondents, the percentage of respondents from the 46–55 age group who ranked the film excellent exists at 5.605%.
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Answer:
h= 2/3d
Step-by-step explanation:
slope is the change of y value on the change of x value
4/6 = 2/3
12Answer:
Step-by-step explanation:
Answer: Step-by-step explanation: We are given an exponential equation.We need to convert it into it's equivalent equation.Let us factor 4.4 = 2 × 2Therefore, 2 × 2 could be written as .Now, let us factor 64 in terms of 2's.64 = 2 × 2× 2× 2× 2× 2 = .Replacing 4 by and 64 by in original equation, we get Distributing 2 over (x+3), we get
Answer:
Step-by-step explanation:
2y = -x +9
3x - 6y = -15
The solution is the value of x and y that will make the two equations true in the same time.
3x-6y = -15; divide both sides by 3
x-2y = -5; substitute 2y for -x+9 because the first equation tell us they are equal
x-(-x+9) = -5; open parenthesis
x+x-9 = -5 ; add 9 to both sides and combine like terms
2x = -5 +9; 2x = 4; divide both sides by 2
x= 2
Substitute x for 2
2y = -x+9 ; 2y = -2 +9 ; 2y = 7; y = 7/2 = 3.5
Solution is (2, 3.5)
Answer:
Step-by-step explanation:
Regression and Prediction Perhaps the most common goal in statistics is to ... a model to predict individual outcomes for new data, rather than explain data in hand .... overall accuracy of the model, and is a basis for comparing it to other models
