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ohaa [14]
2 years ago
12

Luisa buys a plane ticket that has an original price of $\$240$ . She uses a coupon code to get a $30\%$ discount off of the ori

ginal price. She is then charged a $7\%$ tax on the discounted price.
What is the final cost for Luisa's plane ticket?
Mathematics
2 answers:
stealth61 [152]2 years ago
7 0

Answer:

c

Step-by-step explanation:

andrey2020 [161]2 years ago
6 0

Answer:

179.76

Step-by-step explanation:

If there are 240 dollars then minus 30%240-30%=168.00Then, plus the 7% 168+7%= 179.76I hope this helps!

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All vectors are in Rn. Check the true statements below:
Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

Proy_{cv}y=\frac{(y\cdot cv)}{||cv||^2}cv=\frac{c(y\cdot v)}{c^2||v||^2}cv=\frac{(y\cdot v)}{||v||^2}v=Proy_{v}y

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that ||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then ||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||.

C) Consider S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2. This set is orthogonal because (0,2)\cdot(2,0)=0(2)+2(0)=0, but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in \mathbb{R}^n. Then the columns of A form an orthonormal set. We have that A^{-1}=A^t. To see this, note than the component b_{ij} of the product A^t A is the dot product of the i-th row of A^t and the jth row of A. But the i-th row of A^t is equal to the i-th column of A. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then A^t A=I    

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set \{u_1,u_2\cdots u_p\} and suppose that there are coefficients a_i such that a_1u_1+a_2u_2\cdots a_nu_n=0. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then a_i||u_i||=0 then a_i=0.  

5 0
3 years ago
Which postulate proves the two
adoni [48]

Answer:

the answer is b and i need atleast twenty words so it is asa because the middle and side and the right angle

7 0
2 years ago
How do I solve this proportion??<br> 7/n = 8 / 7
kirill115 [55]
\frac{7}{n}=\frac{8}{7} \\\\ n=\frac{7*7}{8} \\\\ \boxed{n=\frac{49}{8}}
7 0
3 years ago
Read 2 more answers
3 • X = 5.25.<br> What is X?
Archy [21]
Your answer will be x=1.75
3 0
3 years ago
Read 2 more answers
5x-3y when x=7 and y=-8
I am Lyosha [343]
5 (7) - 3 (-8)

35 - -24

Because two negatives equal a positive the subtraction sign will change into an addition sign.

35+24

So your answer will be 59.

Hope this helped :)
5 0
3 years ago
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