Let
d = the total number of dairy cattle
b = the total number of beef cattle
2/3 of the dairy cattle on a farm are in the barn, and we know that 24 dairy cattle are in the barn thus:
(2/3)d = 24
d = 36 dairy cattle
1/4 of the beef cattle are in the barn and there are 16 beef cattle in the barn thus:
(1/4)b = 16
b = 64 beef cattle
64 - 36 = 28
There are 28 more beef cattle on the farm than dairy cattle.
Answer:
x = 4 radical 3 / 3
Step-by-step explanation:
this is a 30-60-90 triangle
the side across from the angle 30 is L
the side across from the angle 60 is L√3
the side across from the angle 90 is 2L
we are given the side across from 60⁰ so we know that:
2 = L√3
we want to solve for L, so we must divide both sides by √3 (radical three)
2/√3 = L√3/√3
you would get 2/ √3 = L, because the radical three cancels out on the L side.
but you can't have a radical in the denominator, so you have to multiply 2/√3 by radical 3
2 times √3 and √3 times √3
you get 2√3/√9
radical nine can simplify
2radical3/3 or 2√3/3
we found L, but that would equal the thirty degree angle, not the 90, 90 = 2L
multiply the number infront of the radical by two and get
4√3/3
x=4 radical 3 divided by 3
Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).
Let <em>x</em> be the inverse. Then <em>x</em> is such that
23<em>x</em> ≡ 1 (mod 1000)
Use the Euclidean algorithm to solve for <em>x</em> :
1000 = 43×23 + 11
23 = 2×11 + 1
→ 1 ≡ 23 - 2×11 (mod 1000)
→ 1 ≡ 23 - 2×(1000 - 43×23) (mod 1000)
→ 1 ≡ 23 - 2×1000 + 86×23 (mod 1000)
→ 1 ≡ 87×23 - 2×1000 ≡ 87×23 (mod 1000)
→ 23⁻¹ ≡ 87 (mod 1000)
Since 20<span> is the largest number </span>common<span> to both lists, the </span>GCF<span> of 40 and </span>60<span> is </span>20<span>.</span>
143 cards, you can find this using the LCM or least common multiple. <span />
