Answer:
9.34%
Step-by-step explanation:
p = 4%, or 0.04
n = Sample size = 667
u = Expected value = n * p = 667 * 0.04 = 26.68
SD = Standard deviation = 
= 5.06
Now, the question is if the manager is correct, what is the probability that the proportion of flops in a sample of 667 released films would be greater than 5%?
This statement implies that the p-vlaue of Z when X = 5% * 667 = 33.35
Since,
Z = (X - u) / SD
We have;
Z = (33.35 - 26.68) / 5.06
Z = 1.32
From the Z-table, the p-value of 1.32 is 0.9066
1 - 0.9066 = 0.0934, or 9.34%
Therefore, the probability that the proportion of flops in a sample of 667 released films would be greater than 5% is 9.34%.
Answer:
a is the correct option.
Step-by-step explanation:
We have been given the population model is 
Here x represents number of weeks and f(x) is population of frog after x weeks.
For x= 6, we have
It means that the population after 6 weeks is 960.
Hence, f(6)=960 represents the population after 6 weeks.
a is the correct option.
Answer: 4
Step-by-step explanation:
The procedure is pretty basic. First you have to substitute what you know in the equation. So as you know f(x)=18, just substitute f(x) by 18, leaving it like 18 = 3x + 6.
Then you have to start to move things around. First start with the + 6 that is adding, so it moves to the other side as a substraction giving 18 - 6 = 3x -> 12 = 3x. The next step is to get rid of that 3, so because it's multiplying the x, it moves to the other side as a division leaving you with 12 ÷ 3 = x -> 4 = x. There you have the answer! For a value/y of 18 in that function, the x is 4
The answer is $8.75. You have to find what one costs which is 1.25 so if you have 7. 1.25 times 7 is $8.75
Answer:
get a life its c
Step-by-step explanation:
