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erik [133]
3 years ago
15

What is the point slope of an equation with slope of 3/5 that passes through the point (10,-2)

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
6 0
Y - y_1 = m(x - x_1)
y - (-2) = 3/5(x - 10)
y + 2 = 3/5(x - 10)

The answer is B.
Verdich [7]3 years ago
4 0
The answer would be B. It gives you the slope and a point on the graph so use that to your advantage. All of the answers show the slope and the slope in the right place, so for now it can be any of them. Then we get to the point (10,-2). For point slope form you would switch the signs for both x and y. So the Y would now be +2 and x would be -10. Y goes together with y, and X goes together with x. In this case y+-y= slope(X+-x) Substitute in for them. Y+2=3/5(X-10)
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round it to a whole number of 100 m witch i think would be 15700 m

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3 years ago
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A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 36 ​centimeters, and the l
DochEvi [55]

Answer:

45.6 cm

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2 years ago
Felix wrote several equations and determined that only one of the equations has no solution. Which of these equations has no sol
lara [203]

Answer:

3(x-2)+x=4x+6

Step-by-step explanation:

case 1) we have

3(x-2)+x=4x-6

Solve for x

3x-6+x=4x-6

4x-6=4x-6

0=0 ----> is true for any value of x

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3(x-2)+x=2x-6

3x-6+x=2x-6

4x-2x=-6+6

2x=0

x=0

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4x-3x=-3+6

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case 4) we have

3(x-2)+x=4x+6

3x-6+x=4x+6

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4 0
2 years ago
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Can someone pls help for brainlest
gregori [183]

Diameter of the semicircle = 10 km.

Explanation:  perimeter of semicircle =   1  2

the circumference + diameter  Given: perimeter of semicircle =  25.7  k m

Circumference of circle with radius  r =  2 π r  where  2 r = diameter  ⇒ 25.7 = 22 π r + 2 r ⇒ 25.7 = π r + 2 r = r ( π + 2 )  ⇒ 25.7 = r ( 3.14 + 2 ) = r ( 5.14 )  ⇒ r = =5m ⇒d i a m e t e r = 2 r = 10 k m

5 0
2 years ago
Find the roots of the polynomial equation.
True [87]

Answer:

3 ± i5

Step-by-step explanation:

Here we're given four sets of possible roots of the given polynomial.   Each set consists of two complex quantities and 1 real quantity.

First, we determine whether +4 is a root, then whether -4 is a root.  Let's use synthetic division to do that:

     -----------------------

4   /  1   -2    10   136

             4      8    72

    ---------------------------

        1     2    18    208     Since the remainder is not zero, 4 is not a root.

Eliminate the first two possible answer choices, and assume that -4 is a root.

Let's check this out to be certain:

     -----------------------

-4  /  1   -2    10   136

             -4   24  -136

    ---------------------------

        1     -6    34    0

Since the rem. is zero, -4 is a root, and the coefficients of the 2nd-degree quotient are 1, -6 and 34.

In other words, a = 1, b = -6 and c = 34.

Let's apply the quadratic rule to find the roots:

       6 ± √(36 - 4[1][34] )       6 ± √ (-100)

x = ------------------------------ = ----------------------- = 3 ± i5

                     2                                   2

So the correct answer is the last one of the four given possible answers:

3 ± i5

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3 years ago
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