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erik [133]
3 years ago
15

What is the point slope of an equation with slope of 3/5 that passes through the point (10,-2)

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
6 0
Y - y_1 = m(x - x_1)
y - (-2) = 3/5(x - 10)
y + 2 = 3/5(x - 10)

The answer is B.
Verdich [7]3 years ago
4 0
The answer would be B. It gives you the slope and a point on the graph so use that to your advantage. All of the answers show the slope and the slope in the right place, so for now it can be any of them. Then we get to the point (10,-2). For point slope form you would switch the signs for both x and y. So the Y would now be +2 and x would be -10. Y goes together with y, and X goes together with x. In this case y+-y= slope(X+-x) Substitute in for them. Y+2=3/5(X-10)
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A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

8 0
3 years ago
The ratio of tagged fish to untagged fish was 2 to 9. Ninety fish were tagged. How many fish were untagged
Nimfa-mama [501]

Answer:

405

Step-by-step explanation:

Since

2 : 9 = 90 : X

Then we know

9/2 = X/90

Multiplying both sides by 90 cancels on the right

90 × (9/2) = (X/90) × 90

90 × (9/2) = X

Then solving for X

X = 90 × (9/2)

X = 405

Therefore

2 : 9 = 90 : 405

5 0
3 years ago
5/7 to 9/14 what is the answer
Viefleur [7K]

Answer:


Step-by-step explanation:

5/7 - 9/14 = (2 * 5)/(2 * 7) - (1 * 9)/(1 * 14) = 10/14 - 9/14 = (10 - 9)/14 = 1/14

3 0
3 years ago
Please help! I just need the second question answered given the first is correct.
Nataliya [291]

Answer: 0.970 ??

Step-by-step explanation:

5 0
3 years ago
What is the graph of linear inequality 2y>x-2
pickupchik [31]

Answer:

Please refer to the attached graph for the graph of linear inequality:

2y>x-2

Step-by-step explanation:

Method to draw graph of inequality:

<u>1. First of all replace the inequality sign with equality.</u>

Now the equation is:

2y=x-2

Now, find point and plot them.

Let us put x = 0, we get y = -1. So one point is <em>(0, -1)</em>

Let us put y = 0, we get x = 2. So one point is <em>(2,0)</em>

Now, plot both the point and join with straight line on xy coordinate axis.

2. Now, try to find a random point and put in the inequality.

If the point satisfies the inequality shade the region moving from the line towards that point.

For example:

Taking a point (4, 2)

Putting in the inequality:

8 > 2-2 \\8>0

So, (4, 2) satisfies the inequality.

Now, shade the region moving from the line towards the point (4,2).

We get the shaded region as shown in the attached figure in the answer area.

3 0
3 years ago
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