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Nady [450]
1 year ago
9

In triangle QRS, angle Q measures 33.7°, angle R measures 52.3°, and angle S measures 94°. Based on the information that is prov

ided, which could be a correct set of sides for this set of angles?
side QR = 7 cm , side RS = 10 cm , side QS = 12.6 cm
side QR = 10 cm, side RS = 7 cm, side QS = 12.6 cm
side QR = 12.6 cm, side RS = 10 cm, side QS = 7 cm
side QR = 12.6 cm, side RS = 7 cm, side QS = 10 cm
Mathematics
1 answer:
ratelena [41]1 year ago
6 0

Answer:

side QR = 12.6 cm, side RS = 7 cm, side QS = 10 cm

Step-by-step explanation:

The side opposite to biggest angle is the longest side

         In ΔQRS,

∠S > ∠R > ∠Q

∠S is the biggest and ∠ Q is the smallest angle.

So, the side opposite to ∠S, QR is the longest side and the side opposite o ∠Q , RS is the smallest side.

QR > QS > RS

QR = 12.6 cm  ; QS = 10 cm and  RS = 7 cm

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W is less than or equal to – 2 and greater than or equal to - 8
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Answer:

-8 ≤w ≤-2

Step-by-step explanation:

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3 years ago
the 43rd term of an arithmetic sequence is -671 and the 52nd term is -806. find the first term and the common difference.
Bond [772]

Answer:

First term = -41.

Common difference = -15.

Step-by-step explanation:

nth term: an = a1 + (n - 1)d  where a = first term and d = the common difference.

-671 = a1 + (43 - 1)d

-806 = a1 +(52 - 1)d

-671  = a1 + 42d

-806 = a1 + 51d

Subtracting ( to eliminate a1):

-671 - (-806) = 42d - 51d

-9d =  135

d = -15

Substitute for d in the first equation:

-671 = a1 + 42*-15

-671 = a1 - 630

a1 = -671 + 630 = -41.

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2 years ago
10.
Pie

Answer:

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3 years ago
Read 2 more answers
2564.0 millimeters tall. If the boards are too long they must be trimmed, and if the boards are too short they cannot be used. A
Leokris [45]

Answer:

We conclude that the board's length is equal to 2564.0 millimeters.

Step-by-step explanation:

We are given that a sample of 26 is made, and it is found that they have a mean of 2559.5 millimeters with a standard deviation of 15.0.

Let \mu = <u><em>population mean length of the board</em></u>.

So, Null Hypothesis, H_0 : \mu = 2564.0 millimeters    {means that the board's length is equal to 2564.0 millimeters}

Alternate Hypothesis, H_A : \mu \neq 2564.0 millimeters      {means that the boards are either too long or too short}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                             T.S.  =  \frac{\bar X-\mu}{\frac{s }{\sqrt{n}} }  ~  t_n_-_1

where, \bar X = sample mean length of boards = 2559.5 millimeters

            s = sample standard deviation = 15.0 millimeters

             n = sample of boards = 26

So, <em><u>the test statistics</u></em> =  \frac{2559.5-2564.0}{\frac{15.0 }{\sqrt{26}} }  ~   t_2_5

                                     =  -1.529    

The value of t-test statistics is -1.529.

Now, at a 0.05 level of significance, the t table gives a critical value of -2.06 and 2.06 at 25 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so <u><em>we have insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the board's length is equal to 2564.0 millimeters.

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Find the value of x.
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Step-by-step explanation:

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