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OverLord2011 [107]
3 years ago
15

9. Samantha had $30 to spend on five pens. After buying them he had $4.75. How much did each pen cost? WILL GIVE BRAINLIEST AND

MEED WORK DONE​
Mathematics
1 answer:
Stells [14]3 years ago
7 0

Answer:

$5.05

Step-by-step explanation:

$30-4.75=25.25 (cost of total pens)

25.25÷5=$5.05 (there are 5 pens so divide by 5)

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During a scuba dive, Lainey descended to a point 20 feet below the ocean surface.She countined her descent at a rate of 20 feet
lorasvet [3.4K]

Answer:

20 + 20x \leq 100

Step-by-step explanation:

Let x be the number of minutes she can continue, since she's already 20 feet below the ocean surface and is diving at the rate of 20 ft/minute, her depth with respect to x would be

20 + 20x

But she doesn't want to reach more than 100 feet below the surface

20 + 20x \leq 100

4 0
3 years ago
Write an equation for a parabola with x-intercepts (-4,0) and (5,0) which passes through the point (3. – 28).
Vanyuwa [196]

Answer:

y=a(x-p)(x-q)

y=a(x+2+√2)(x+2-√2)

passing through point (-1,1)

substitute

1=a(-1+2+√2)(-1+2-√2)

1=a(1+√2)(1-√2)

1=a(1-2)

1=a(-1)

a=1/(-1)

a=-1

y=-(x+[2+√2])(x+[2-√2])

y=-(x2+4x+2)

Thanks rate 5 stars

5 0
4 years ago
What would the fraction 63/98 be if it was simplified?
jeka94
Divide both 63 and 98 by 7, which gives you 9/14
4 0
3 years ago
Read 2 more answers
Hellpppppppppspspspspspspsp
Black_prince [1.1K]

I'd say 13, hope this helps

Step-by-step explanation:

3 0
3 years ago
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If y varies directly as x and x = 9 when y = 15 , find y when x = 33
poizon [28]
This would practically be very reliable of course. We can see in the sentence above that y and x, and x and y are both depending on each other. So, now that this has been considered, we can see that whenever "x" would be a certain number, this would show you that "y" would also be a certain number, and depending how much "x" or "y" would move, it would also change these variable no matter how they move.

This would be a matter of division. As we can see above on how 9 and 15 could be divisible down the line as they multiply.

Therefore, we would then see how many times would "x" which is 9, how many times that would go in 33.

Let's start!

\boxed{33\div9= \ (3.6)}

We take this "3.6" away from this, and we would plug it into "y".

We then do the following:

\boxed{3.6*15=55}

Therefore, when "x" = 33, "y" would then equal 55.

Your answer: \boxed{\boxed{\bf{y=55}}}
5 0
3 years ago
Read 2 more answers
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