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3 years ago

GIVING BRAINLIEST, SIMPLE 7TH GRADE MATH PROBLEM.

Mathematics

1 answer:

Firlakuza [10]3 years ago

8 0

55°
Subtract 70 from 180, giving you 110. Divide this by 2. That’s how you get the measure of angle A and angle B.

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September 5, 1793 - July 27, 1794

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3 years ago

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-4 1/2 ÷ (-2 2/3)<br><br> I need it as a mixed number in simplified form.

Leya [2.2K]

(-4 1/2) / (-2 2/3) =.....turn to improper fractions
(- 9/2) / (-8/3) =...when dividing fractions, flip what u r dividing by, then multiply

-9/2 * -3/8 =
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3 years ago

The parallelogram is dilated by a scale factor of

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Answer:

(2,1)

Step-by-step explanation:

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3 years ago

There are some goats, cows and, sheep. 2/5 of the animals were goats. There were three times as many sheep than cows. If there w

kobusy [5.1K]

Answer:

81 sheep were there on the farm

Step-by-step explanation:

Consider the provided information.

Let x represents the number of goats.

y represents the number of cows.

z represents the number of sheep.

Therefore, the total number of animals are x+y+z

2/5 of the animals were goats. This can be written as:

$\frac{2}{5}(x+y+z)=x$

There were three times as many sheep than cows.

$z=3y$

There were 45 more goats than cows,

$x=45+y$

Substitute the value of x and z in equation 1.

$\frac{2}{5}(45+y+y+3y)=45+y$

$\frac{2}{5}(45+5y)=45+y$

$2(9+y)=45+y$

$18+2y=45+y$

$y=27$

Hence, there are 27 cows.

Substitute the value of y in $x=45+y$

$x=45+27$

$x=72$

Therefore, there are 72 goats.

Substitute the value of y in $z=3y$

$z=3(27)$

$z=81$

Thus, there are 81 sheep.

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3 years ago

A bag contains 42 red,45 green, 20 yellow and 32 purple candies you pick one candy at random find the probability that it is gre

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Answer:

Probability 29%

Step-by-step explanation:

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2 years ago