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klasskru [66]
2 years ago
10

Write an equation of the line with the given slope and y-intercept,(4,3) and (0,1)

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
5 0

Answer:

y=1/2x+1

Step-by-step explanation:

First use slope formula.

\frac{y2-y1}{x2-x1}

Plug in the information needed.

\frac{1-3}{0-4}=\frac{-2}{-4}=\frac{1}{2}

The slope is \frac{1}{2}.

Now, use point-slope formula.

y-y1=m(x-x1)

Plug in the information needed.

y-3=1/2(x-4)

y-3=1/2x-2

y=1/2x+1

The equation of the line in slope-intercept form is y=1/2x+1.

Hope this helps!

If not, I am sorry.

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Write the equation of a circle for which the endpoints of a diameter are (-2,-2) and (4,-10)
Maurinko [17]

Answer:

Therefore the required Equation of Circle

x^{2}+y^{2}-2x+12y+12=0

Step-by-step explanation:

Given:

End point of Diameter be

point A( x₁ , y₁) ≡ ( -2 ,-2 )

point B( x₂ , y₂) ≡ ( 4 , -10 )

To Find:

Equation of a circle =?

Solution:

When end points of the Diameter are A( x₁ , y₁) , B( x₂ , y₂). then the Equation of Circle is given as

(x-x_{1})(x-x_{2})+(y-y_{1})(y-y_{2})=0

Substituting the end point are

(x-(-2))(x-4)+(y-(-2))(y-(-10))=0\\(x+2))(x-4)+(y+2))(y+10))=0\\

Applying Distributive Property we get

x^{2} -2x-8+y^{2}+12y+20 =0\\\\x^{2}+y^{2}-2x+12y+12=0

Therefore the required Equation of Circle

x^{2}+y^{2}-2x+12y+12=0

6 0
3 years ago
Estimate a 15% tip on a dinner bill of 39.51
tatyana61 [14]

Answer:

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Tip Each Person: $ 6

Total (Bill + Tip): $ 46

8 0
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How do you solve this problem?
vodomira [7]
7x^2 - 32x - 60

Factor by grouping,

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6 0
3 years ago
If PQ is tangent to circle R at point Q and PS is
Murljashka [212]

Answer:

Perimeter of the quadrilateral PQRS is 25 units

Step-by-step explanation:

From the figure attached,

PQ is a tangent to the given circle so m∠PQR = 90°

Now we apply Pythagoras theorem in the ΔPQR,

PR² = PQ² + QR²

(PT + TR)²= PQ² + 5²

(4 + 5)² = PQ² + 25

81 = PQ² + 25

PQ = √(81 - 25)

     = √56

     ≈ 7.5 units

PQ ≅ PS ≅ 7.5 units

[Since measures of tangents drawn from a point to a circle are always equal]

Perimeter of PQRS = PQ + QR + RS + PS

                                = 7.5 + 5 + 5 + 7.5

                                = 25 units

Therefore, perimeter of the quadrilateral PQRS is 25 units.

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Solve 732,178 + 167 - 542,137
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Ok I got 190,208
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