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tresset_1 [31]
3 years ago
6

Fill in the blank with +,-,×,÷ to make a true statement on the top and fill in each blank with the given numbers to make a true

statement.( Only use the numbers given once.)

Mathematics
1 answer:
DedPeter [7]3 years ago
7 0
2 / , X5 X , /, –6 /, –, –7 /, /, /, –
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How many degrees is the missing angle?<br><br> (Fill in the blank HURRY PLEASE) I’ll give brainliest
velikii [3]

Answer:

x = 55°

Step-by-step explanation:

x = 180° - 85° - 40° = 55°

5 0
3 years ago
Read 2 more answers
The following table shows scores obtained in an examination by B.Ed JHS Specialism students. Use the information to answer the q
Makovka662 [10]

Answer:

(a) The cumulative frequency curve for the data is attached below.

(b) (i) The inter-quartile range is 10.08.

(b) (ii) The 70th percentile class scores is 0.

(b) (iii) the probability that a student scored at most 50 on the examination is 0.89.

Step-by-step explanation:

(a)

To make a cumulative frequency curve for the data first convert the class interval into continuous.

The cumulative frequencies are computed by summing the previous frequencies.

The cumulative frequency curve for the data is attached below.

(b)

(i)

The inter-quartile range is the difference between the third and the first quartile.

Compute the values of Q₁ and Q₃ as follows:

Q₁ is at the position:

\frac{\sum f}{4}=\frac{100}{4}=25

The class interval is: 34.5 - 39.5.

The formula of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 25 = 34.5

(CF)_{p} = cumulative frequency of the previous class = 24

f = frequency of the class interval = 20

h = width = 39.5 - 34.5 = 5

Then the value of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

     =34.5+[\frac{25-24}{20}]\times5\\\\=34.5+0.25\\=34.75

The value of first quartile is 34.75.

Q₃ is at the position:

\frac{3\sum f}{4}=\frac{3\times100}{4}=75

The class interval is: 44.5 - 49.5.

The formula of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 75 = 44.5

(CF)_{p} = cumulative frequency of the previous class = 74

f = frequency of the class interval = 15

h = width = 49.5 - 44.5 = 5

Then the value of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

     =44.5+[\frac{75-74}{15}]\times5\\\\=44.5+0.33\\=44.83

The value of third quartile is 44.83.

Then the inter-quartile range is:

IQR = Q_{3}-Q_{1}

        =44.83-34.75\\=10.08

Thus, the inter-quartile range is 10.08.

(ii)

The maximum upper limit of the class intervals is 69.5.

That is the maximum percentile class score is 69.5th percentile.

So, the 70th percentile class scores is 0.

(iii)

Compute the probability that a student scored at most 50 on the examination as follows:

P(\text{Score At most 50})=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}

                                 =\frac{10+4+10+20+30+15}{100}\\\\=\frac{89}{100}\\\\=0.89

Thus, the probability that a student scored at most 50 on the examination is 0.89.

5 0
3 years ago
Hip hop music makes up 75% of Landon's music library. If he has downloaded 120 hip hop songs, how many songs does Landon have in
Otrada [13]

Answer: 160 songs.

Step-by-step explanation:

<em>75% hip hop music   -    120 songs </em>

<em>100% all music          -     x songs </em>

<em>Let's write the proportion:</em>

<em />\dfrac{120}{75} =\dfrac{x}{100} \\\\75x=120 \cdot 100\\75x=12000\\75x : 75 = 12000 : 75\\x = 160<em />

<em>Thus, Landon have 160 songs in his music library.</em>

4 0
3 years ago
Write the standard form of the equation of the line through (4, 4) and parallel to y = -6x + 5.
valina [46]

Answer:

y

=

−

6

x

+

5

.

y

=

−

6

x

+

28

Step-by-step explanation:

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2 years ago
This is a pre calculus question that I need help with, serious answer PLEASE and thank you! Will give brainliest.
IRISSAK [1]

The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

\dfrac12,\dfrac14,\dfrac18,\ldots,\dfrac1{64}

which would be

\dfrac12+\dfrac14+\dfrac18+\cdots+\dfrac1{64}

in sigma notation.

To do this, notice that the denominator in each term is a power of 2, starting with 2^1=2 and ending with 2^6=64. So in sigma notation, this series is

\displaystyle\sum_{n=1}^6\frac1{2^n}

4 0
3 years ago
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