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Lady_Fox [76]
1 year ago
5

Height of 24cm with a radius of 7cm. What is the total surface area of the cone?

Mathematics
1 answer:
True [87]1 year ago
4 0

Answer:

the answer to this problem is 703.7 in^2

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Let the equation of a line be described by Equation A:
umka2103 [35]
10y - 5x = 40   Add 5x to both sides
       10y = 5x + 40   Divide both sides by 10
          y = \frac{1}{2}x + 4

The y-intercept is 4 and the slope of the line is \frac{1}{2}.

You can find these by comparing your equation to the equation y = mx + b, where m is the slope of the line and b is the y-intercept.
4 0
3 years ago
Use the table for 19-23. write each ratio in the form a/b and then as a decimal. Tell whether each decimal is a terminating or r
stellarik [79]
All you are basically doing is making ratios.
Basketball to football would be 5 to 11 or 5:11 or 5/11.
What you do is in the order you said it (basketball to football) you find that info and make it a ratio. A ratio must be simplified and can be written 3 ways, as shown above.

Hockey to lacrosse would be 6 to 10 and simplified would be 3 to 5.

Try doing 3 and 4 and 5 on your own to help you understand it more:) if you have any questions tell me.
4 0
2 years ago
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A store pays $10 for a bracelet,and the markup is 115%. A customer will also pay a 5 and 1/2% sales tax.What will be the total c
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31.76 and to the power of 9 is somethinng
4 0
3 years ago
A string of decorative lights is 22 feet long. The first light on the string is 16 inches from the plug. The
Masteriza [31]

Answer:

63 Lights

Step-by-step explanation:

First you can convert the feet to inches:

The length of decorative lights is 264 inches

You can then subtract 16 from 264

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Adding one extra light at the end of the string of decorative lights you can get 63 lights on the string

5 0
2 years ago
1. What is the solution of n² – 49 = 0? (1 point)
maks197457 [2]

Answer:

1. n=\pm7

2. x=\pm7i[tex]3.[tex]\pm 12x =a

4. 22

Step-by-step explanation:

1. n^2 - 49 = 0

n^2 =49

n= \sqrt{49}

n=\pm7

2. x^2+64 = 0

x^2 =-64

x= \sqrt{49}

x=\pm7i[tex]3. Area of square = [tex]a^{2}

Where a is the side

We are given an area o square = 144x^{2}

So, 144x^{2}=a^{2}

\sqrt{144x^{2}}=a

\pm 12x =a

4. We are given that the solution of quadratic equation -9 and 9

So, equation becomes:

(x+9)(x-9)=0

x^2- 81=0

So, in the given equation x^2 + z = 103

z should be the number from which if we subtract 103 so we get 81

Substitute z = 22

x^2 + 22 = 103

x^2 + 22 -103=0

x^2 -81=0

Thus the value of z is 22

8 0
3 years ago
Read 2 more answers
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