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Agata [3.3K]
3 years ago
7

Please help!! I don't get it!!

Mathematics
1 answer:
Trava [24]3 years ago
5 0

Find the line for each given equation in the problem.

If they cross each other  ( at least one solution) it is consistent.

If they do not cross each other at all, it is inconsistent.

If a consistent system has only one answer it would be independent.

If a consistent system has infinite solutions ( this would be just a straight line) it would be dependent.

If there are no solutions, it is neither dependent or independent.


1. Both lines cross each other in one place, so this is consistent and independent.


2. Both lines cross each other in one place, so this is consistent and independent.


3. The two lines do not cross each other, so this is inconsistent.

There are no solutions, so this is neither dependent or independent.


4. Both lines cross each other in one place, so this is consistent and independent.


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Suppose that z=6^500. Express the following in terms of z.
Studentka2010 [4]

Answer:

1. z^2

2. 14z

Step-by-step explanation:

  • We know that (a^m)^n = a^(mn) = (a^n) ^m

We also know that (a^m)(a^n) = a^(m+n)

  1. 36 can be written as 6^2 and here 36^(500) can be written as (6^2)^500 which also can be written as (6^500)^2 and as already it is mentioned that 6^500 as z we can write the above as <u>z^2</u>

2. 8 x 6^500 = 8z

And we can also write 6^(501) as 6^(500+1) which is equivalent to 6(6^500) which is 6z.

From the above we can make sure that the question is the sum of the above which is 8z + 6z = <u>14z</u><u>.</u>

7 0
3 years ago
Suppose that 20% of the employees of a given corporation engage in physical exercise activities during the lunch hour. Moreover,
Harlamova29_29 [7]

Answer:

a) 0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.

b) 0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.

Step-by-step explanation:

Question a:

20% of employees engage in physical exercise.

This 20% is composed by:

8% of 60%(males)

x% of 100 - 60 = 40%(females).

Then, x is given by:

0.08*0.6 + 0.4x = 0.2

0.4x = 0.2 - 0.08*0.6

x = \frac{0.2 - 0.08*0.6}{0.4}

x = 0.38

0.38 = 38%

Probability of being a female who engages in exercise:

40% are female, 38% of 40% engage in exercise. So

0.38*0.4 = 0.152

0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.

B. If we choose an employee at random from this corporation,what is the probability that this person is a female who does not engage in physical exercise activities during the lunch hour?

40% are female, 100% - 38% = 62% of 40% do not engage in exercise. So

0.62*0.4 = 0.248

0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.

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The greatest comment factor of 28 and 64 is 4.

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the greatest one of the two factors is 4.
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