Answer:
findgreater(83, 71)
Step-by-step explanation:
Basically to call a function you do:
FunctionName()
sometimes, these functions have some parameters (engine1 and engine2) and you need to give some values to those (83, 71). When you faced a problem like this you'll put those values (83, 71) in the parentheses which are next to the functionname (as shown above).
FunctionName(Value1, Value2, ...)
By replacing the point (-1, 4) into the first inequality y<= -(x)+4
4<= - (-1)+4
4<=1+4
4<=5 (this implies that this is the answer).
<span><span><span><span><span>(<span><span>3x</span>−4</span>)</span><span>(<span>2x</span>)</span></span><span>(2)</span></span>+<span>2x</span></span>−1
</span>Distribute:
<span>=<span><span><span><span><span><span>12<span>x2</span></span>+</span>−<span>16x</span></span>+<span>2x</span></span>+</span>−1
</span></span>Combine Like Terms:
<span>=<span><span><span><span>12<span>x2</span></span>+<span>−<span>16x</span></span></span>+<span>2x</span></span>+<span>−1</span></span></span><span>=<span><span><span>(<span>12<span>x2</span></span>)</span>+<span>(<span><span>−<span>16x</span></span>+<span>2x</span></span>)</span></span>+<span>(<span>−1</span>)</span></span></span><span>=<span><span><span>12<span>x2</span></span>+<span>−<span>14x</span></span></span>+<span>−1
</span></span></span>Answer:<span>=<span><span><span>12<span>x2</span></span>−<span>14x</span></span>−<span>1
hope this helps! was there meant to be a parenthesis by the 2 + 2x - 1?? </span></span></span>
