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Ivanshal [37]
3 years ago
6

Solve the quadratic equation for the solutions. f(x) = 2x^2 - 6x + 10

Mathematics
1 answer:
NikAS [45]3 years ago
8 0
I’m a little rusty but I got 8
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What points should I circle and in which point do they intersect?
Masteriza [31]

Answer:

\displaystyle [3, -2]

Explanation:

All you do is substitute three in for \displaystyle xto get the y-coordinate of \displaystyle -2.This means that these equations meet at the ordered pair of \displaystyle [3, -2].

I am joyous to assist you at any time.

6 0
2 years ago
Are the triangles similar? If so, find x. Please help
dsp73

Answer:

there is one in the middile i hop it helps

Step-by-step explanation:

okay

3 0
3 years ago
A color printer prints 21 pages in 6 minutes.<br> How many pages does it print per minute?
masya89 [10]

Answer:

3.5

Step-by-step explanation:

21  (pages) divided by 6 (minutes) = 3.5 per minute

3 0
3 years ago
How do I factor the following equation in the link? It has been factored, but I need to know the steps.
Vlad [161]

Given

2x^2-x-3=0

How to factor

Solution

Step 1

Multiply the first and last costant

-3\times2x^2=-6x^2

Step 2

Write out all the pair factors of -6x^2

\begin{gathered} -6x^2=-6x\text{ and x} \\ -6x^2=-x\text{ and 6x} \\ -6x^2=\text{ -3x and 2x} \\ -6x^2=\text{ -2x and 3x} \end{gathered}

Step 3

Check for the pair, such that when you add you will get -x

\begin{gathered} it\text{ is } \\ -3x+2x=-x \\ \therefore-3x,\text{ 2x} \end{gathered}

Step 4

Replace -x with -3x+2x in the equation

2x^2-3x+2x-3=0

Step 5

Put them into brackets Since + is at the center no stress.

(2x^2-3x)+(2x-3)=0

Step 6

Factor out what is common in the bracket

x(2x^{}-3)+1(2x-3)=0

Step 7

What is in the bracket are the same, pick one

\therefore(2x-3)(x+1)=0_{}

7 0
1 year ago
Use substitution to solve each system of equations.<br><br>x-2y<br>y=x-2​
Helga [31]

Answer:

-x+4

Step-by-step explanation:

x-2y

y= x-2

x-2(x-2)

x-2x+4

-x+4

3 0
4 years ago
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