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enyata [817]
1 year ago
14

What are x and 8 in the linear equation? 8/x+5=50/25

Mathematics
1 answer:
Airida [17]1 year ago
5 0
B because both are variables
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Please help me due tomorrow
Nostrana [21]

Answer:

y=3

Step-by-step explanation:

(i used point-slope form which is (y1-y2)=m(x1-x2))

(10-y)=7(4-3)

10-y=7

-y=-3

y=3

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2 years ago
Help for brainliest and 10 points
Travka [436]

Answer:

-3

Step-by-step explanation:

0.002 = 2 \times  {10}^{ - 3}  \\  \implies \: x =  - 3

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2 years ago
Write the standard form of the equation y+4=12/7(x-1)
Goshia [24]
This is the eqn of a str line.    <span>y+4=12/7(x-1) would be clearer if written as

</span><span>y+4=(12/7)(x-1).     y+4 = (12/7)x - 12/7.  

Multiply all terms by 7 to remove the fractions:  7(y+4) = 12x - 12.

Complete the multiplication:                            7y + 28 = 12x - 12.

Arrange the x and y terms on the left side and the constants on the right:

-12x + 7y = -40.  This is standard form.  Some people might disagree and say that -12x + 7y + 40 is standard form.  They are equivalent.

</span>
5 0
3 years ago
WILL MARK BRAINLIEST!!!
Art [367]

Answer:

<em>I think the best answer will be is</em><em> C. 1.3 Good Luck!</em>

8 0
3 years ago
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The dotted line represents the mid segment of the trapezoid. Find the value of X
Ganezh [65]

<u>Given</u>:

Given that the bases of the trapezoid are 21 and 27.

The midsegment of the trapezoid is 5x - 1.

We need to determine the value of x.

<u>Value of x:</u>

The value of x can be determined using the trapezoid midsegment theorem.

Applying the theorem, we have;

Midsegment = \frac{b_1+b_2}{2}

where b₁ and b₂ are the bases of the trapezoid.

Substituting Midsegment = 5x - 1, b₁ = 21 and b₂ = 27, we get;

5x-1=\frac{21+27}{2}

Multiplying both sides of the equation by 2, we have;

2(5x-1)=(21+27)

Simplifying, we have;

10x-2=48

Adding both sides of the equation by 2, we get;

10x=50

Dividing both sides of the equation by 10, we have;

x=5

Thus, the value of x is 5.

6 0
3 years ago
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