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Alex
2 years ago
8

Which expression is equivalent to (startfraction 4 m n over m superscript negative 2 baseline n superscript 6 baseline endfracti

on) superscript negative 2? assume m not-equals 0, n not-equals 0.
Mathematics
1 answer:
ohaa [14]2 years ago
3 0

The equivalent expression to \left(\frac{4mn}{m^{-2}n^6}\right)^{-2} is given by =\mathbf{\frac{n^{10}}{16m^6}}.

From the principle of indices we get,

Addition of exponent, a^{m+n}=a^m.a^n

Subtraction, a^{m-n}=\frac{a^m}{a^n}

Multiplication, a^{mn}=(a^m)^n

negative exponent, a^{-m}=\frac{1}{a^m}

Here in the problem given expression is \left(\frac{4mn}{m^{-2}n^6}\right)^{-2}

Calculating we get,

\left(\frac{4mn}{m^{-2}n^6}\right)^{-2}

=\left(4m^{1-(-2)}n^{1-6}\right)^{-2}, using addition and subtraction of indices formulae

=\left(4m^3n^{-5}\right)^{-2}

=16^{-1}m^{-6}n^{10}, using multiplication of indices

=\frac{n^{10}}{16m^6}, using negative exponent formula

Hence the equivalent required expression is =\frac{n^{10}}{16m^6}.

Learn more about Indices here -

brainly.com/question/170984

#SPJ10

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