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astraxan [27]
3 years ago
8

If the area of a square is 38 less than 2 times the area of a hexagon, and the sum of the areas of the square and hexagon is 46,

what are the areas of the square and hexagon?
Mathematics
2 answers:
ANTONII [103]3 years ago
5 0
\bf \begin{cases}
s=\textit{area of the square}\\
h=\textit{area of the hexagon}
\end{cases}
\\\\\\
\textit{38 less than 2 times the area of a hexagon}\implies \boxed{s}=2h-38
\\\\\\
\textit{we also know that their sum is }\implies s+h=46
\\\\\\
\boxed{2h-38}+h=46\implies 3h=46+38\implies 3h=84
\\\\\\
h=\cfrac{84}{3}\implies h=28

what's the area of the square?  well, s = 2h - 38.
hichkok12 [17]3 years ago
4 0
Hexagon is 8 and the square is 24
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5 0
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Alexxx [7]

Answer:

Total charge

=

$

4.25

+

$

1.50

(

m

−

1

)

Total charge for 12 miles  

=

 

$

20.75

Explanation:

Building the rule

The trick with algebra is to think what you would do with numbers, then substitute letters.

Mile number 1 costs

$

4.25

The rest of the miles

⇒

(

total miles

−

1

)

×

$

1.50

Putting this all together we have:

$

4.25

+

(

total miles

−

1

)

×

$

1.50

The question instructs that we are to use the letter m for the total miles so we now have:

$

4.25

+

(

m

−

1

)

×

$

1.50

This would be written as:

$

4.25

+

$

1.50

(

m

−

1

)

So

 Total charge

=

$

4.25

+

$

1.50

(

m

−

1

)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Determine the charge for 12 miles

Total charge

=

$

4.25

+

$

1.50

(

12

−

1

)

Total charge

=

$

4.25

+

$

1.50

(

11

)

Total charge for 12 miles

=

$

4.25

+

$

16.50

 

=

 

$

20.75

Hope this helps you...

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