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3 years ago

I have to solve and round to the nearest tenth

Mathematics

1 answer:

hichkok12 [17]3 years ago

4 0

Answer:

approximately 5.6

Step-by-step explanation:

Cross multiply

16a=90

a=5.625

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What is the value of the discriminant, b2 − 4ac, for the quadratic equation 0 = x2 − 4x + 5, and what does it mean about the num

forsale [732]

(-4)^2-4(1)(5)
16-4(1)(5)
16-4(5)
16-20
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The discriminant is negative so there are no real number solutions.

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3 years ago

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3 years ago

Rewrite the expression in the form 6^n 6^-6/6^-5

oee [108]

Answer:

6^-1

Step-by-step explanation:

6^-6 - (-5) = 6^(-6 + 5) = 6^(-1)

A lot of things are going on in this question. Notice how the 5 is handled. It starts off in the denominator as - 5 and when brought to the numerator it becomes -(-5) which makes it + 5.

The answer is then easy. It is 6^(-6 + 5) = 6^-1

You could give the answer as 1/6 but that is not what the question says.

8 0

3 years ago

Use the expression 5a – 2b – 3 + 2b – 6a.

ella [17]

Answer:

5a + (-6a) + (-2b) + 2b + (-3) = -a -3 or -(a + 3) so first answer is correct because -(a + 3) is the same as -(3 + a)

Step-by-step explanation:

4 0

3 years ago

In the data set below, what is the interquartile range? 7 1 5 5 9 Submit

Marizza181 [45]

Answer:

Step-by-step explanation:

The interquartile range is the difference between the upper quartile and the lower quartile.

First find the median.

The median is the middle value of the data set arranged in ascending order

1 5 5 7 9 ← data in ascending order

↑ median

The lower quartile is the middle value of the data to the left of the median. If there is not an exact middle then it the average of the values on either side of the middle.

1 5

↑ lower quartile = $\frac{1+5}{2}$ = 3

The upper quartile is the middle value of the data to the right of the median.

7 9

↑ upper quartile = $\frac{7+9}{2}$ = 8

Thus

interquartile range = 8 - 3 = 5

3 0

2 years ago

I have to solve and round to the nearest tenth​

I have to solve and round to the nearest tenth