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loris [4]
3 years ago
12

I have to solve and round to the nearest tenth​

Mathematics
1 answer:
hichkok12 [17]3 years ago
4 0

Answer:

approximately 5.6

Step-by-step explanation:

Cross multiply

16a=90

a=5.625

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How much salt should Ilya add to 810g of water to make 10% solution? How much solution will he make? Ilya should add __g of salt
Burka [1]

Answer:

90 g of water should be added and he will make 900 g of solution.

Step-by-step explanation:

Let x g be the amount of salt Ilya add to 810g of water to make 10% solution. Then 810+x g is the amount of new solution. Thus,

810+x - 100%,

x - 10%.

Mathematically,

\dfrac{810+x}{x}=\dfrac{100}{10},\\ \\10(810+x)=100x,\\ \\8100+10x=100x,\\ \\100x-10x=8100,\\ \\90x=8100,\\ \\x=\dfrac{8100}{90}=90\ g.

So 90 g of water should be added and he will make 810+90=900 g of solution.

5 0
2 years ago
Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is
Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since,  its head is twice as likely to occur as its tail.

p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n  = 3

p=\dfrac{2}{3}

q=\dfrac{1}{3}

Now,

P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0
2 years ago
WILL GIVE BRAINLIEST TO FIRST PERSON WHO ANSWERS
Elina [12.6K]

Answer:

its c cause I did all the math

7 0
2 years ago
Factor: 24mn – 16n
Sonja [21]
Take out 8n(3m-2) so B
6 0
2 years ago
Read 2 more answers
Part A. Let $f(x) = x^4-3x^2 + 2$ and $g(x) = 2x^4 - 6x^2 + 2x -1$. Let $a$ be a constant. What is the largest possible degree o
Varvara68 [4.7K]

Answer:

  A.  4

  B.  1

Step-by-step explanation:

The degree of a one-variable polynomial is the largest exponent of the variable.

__

<h3>A.</h3>

For f(x) = x^4 -3x^2 +2 and g(x) = 2x^4 -6x^2 +2x -1, the sum f(x) +a·g(x) will be ...

  (x^4 -3x^2 +2) +a(2x^4 -6x^2 +2x -1)

  = (1 +2a)x^4 +(-3-6a)x^2 +2ax -a

The term with the largest exponent is (1 +2a)x^4, which has degree 4. This term will be non-zero for a ≠ -1/2.

The largest possible degree of f+ag is 4.

__

<h3>B.</h3>

The polynomial sum is ...

  f+bg = (1 +2b)x^4 +(-3-6b)x^2 +2bx -b

When b = -1/2, the first two terms disappear and the sum becomes ...

  f+bg = -x +1/2 . . . . . . a polynomial of degree 1

The smallest possible degree of f+bg is 1.

5 0
2 years ago
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