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Effectus [21]
2 years ago
12

8.3.10 Dave is playing blackjack at his local casino. He starts with $1,000 and on each hand he bets 50% of his money. If he win

s a hand, then he wins whatever he bet, but if he loses a hand, then he loses whatever he bet. After playing 5 hands, he has won 3 hands and has lost 2 hands. How much money does Dave have after the 5 hands? Does it matter which 3 of the 5 hands he won?
Hint: It's often best to think of percent increases and decreases in terms of multiplying the original quantity by some number.
Hint: Suppose Dave has $x before betting half his money on a hand. How much will he have if he wins? How much will he have if he loses?
Mathematics
2 answers:
kherson [118]2 years ago
8 0
3 wins 2 looses 843.75
aleksandr82 [10.1K]2 years ago
4 0

Answer:

The amount Dave got after 3 wins and 2 loose is $843.75. The order of win and loose doesn't matter.

Step-by-step explanation:

- We are given with a word problem

- We are asked to find the amount he had after 5 hands

- We can do this in two steps

Step 1 : Identifying the percentages

Step 2 : Finding the amount left

Step 1 of 2

We are given with a word problem. He bets 50% of his money. If he wins he get his bet, if he loose he will loose the money too. If he wins he will get the money as 150%.

That is, 1.5

If he loose he will loose money by 50%

That is, 0.50

Step 2 of 2

The amount got after 5 hands with 3 wins and 2 loose is,

$$\begin{gathered}1000 \times(1.5)^{3} \times(0.5)^{2}=1000 \times 3.375 \times 0.25 \\1000 \times 0.84375=843.75\end{gathered}$$

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A company with a large fleet of cars wants to study the gasoline usage. They check the gasoline usage for 50 company trips chose
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Answer:

The 95% confidence interval is given by (25.71536 ;28.32464)

And if we need to round we can use the following excel code:

round(lower,2)

[1] 25.72

round(upper,2)

[1] 28.32

And the interval would be (25.72; 28.32)  

Step-by-step explanation:

Notation and definitions  

n=50 represent the sample size  

\bar X= 27.2 represent the sample mean  

s=5.83 represent the sample standard deviation  

m represent the margin of error  

Confidence =88% or 0.88

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Calculate the critical value tc  

In order to find the critical value is important to mention that we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 88% of confidence, our significance level would be given by \alpha=1-0.88=0.12 and \alpha/2 =0.06. The degrees of freedom are given by:  

df=n-1=50-1=49  

We can find the critical values in R using the following formulas:  

qt(0.06,49)

[1] -1.582366

qt(1-0.06,49)

[1] 1.582366

The critical value tc=\pm 1.582366  

Calculate the margin of error (m)  

The margin of error for the sample mean is given by this formula:  

m=t_c \frac{s}{\sqrt{n}}  

m=1.582366 \frac{5.83}{\sqrt{50}}=14.613  

With R we can do this:

m=1.582366*(5.83/sqrt(50))

m

[1] 1.304639

Calculate the confidence interval  

The interval for the mean is given by this formula:  

\bar X \pm t_{c} \frac{s}{\sqrt{n}}  

And calculating the limits we got:  

27.02 - 1.582366 \frac{5.83}{\sqrt{50}}=25.715  

27.02 + 1.582366 \frac{5.83}{\sqrt{50}}=28.325

Using R the code is:

lower=27.02-m;lower

[1] 25.71536

upper=27.02+m;upper

[1] 28.32464

The 95% confidence interval is given by (25.71536 ;28.32464)  

And if we need to round we can use the following excel code:

round(lower,2)

[1] 25.72

round(upper,2)

[1] 28.32

And the interval would be (25.72; 28.32)  

6 0
3 years ago
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