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Effectus [21]
1 year ago
12

8.3.10 Dave is playing blackjack at his local casino. He starts with $1,000 and on each hand he bets 50% of his money. If he win

s a hand, then he wins whatever he bet, but if he loses a hand, then he loses whatever he bet. After playing 5 hands, he has won 3 hands and has lost 2 hands. How much money does Dave have after the 5 hands? Does it matter which 3 of the 5 hands he won?
Hint: It's often best to think of percent increases and decreases in terms of multiplying the original quantity by some number.
Hint: Suppose Dave has $x before betting half his money on a hand. How much will he have if he wins? How much will he have if he loses?
Mathematics
2 answers:
kherson [118]1 year ago
8 0
3 wins 2 looses 843.75
aleksandr82 [10.1K]1 year ago
4 0

Answer:

The amount Dave got after 3 wins and 2 loose is $843.75. The order of win and loose doesn't matter.

Step-by-step explanation:

- We are given with a word problem

- We are asked to find the amount he had after 5 hands

- We can do this in two steps

Step 1 : Identifying the percentages

Step 2 : Finding the amount left

Step 1 of 2

We are given with a word problem. He bets 50% of his money. If he wins he get his bet, if he loose he will loose the money too. If he wins he will get the money as 150%.

That is, 1.5

If he loose he will loose money by 50%

That is, 0.50

Step 2 of 2

The amount got after 5 hands with 3 wins and 2 loose is,

$$\begin{gathered}1000 \times(1.5)^{3} \times(0.5)^{2}=1000 \times 3.375 \times 0.25 \\1000 \times 0.84375=843.75\end{gathered}$$

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KonstantinChe [14]

Answer:

(a+2)(b+2) = 4

Step-by-step explanation:

We are given the following quadratic equation:

2x^2-3x-6=0

Let a a and b be the solution of the given quadratic equation.

Solving the equation:

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We have to find the value of (a+2)(b+2).

Putting the values:

(a+2)(b+2)\\\\=\bigg(\dfrac{3+\sqrt{57}}{4}+2\bigg)\bigg(\dfrac{3-\sqrt{57}}{4}+2\bigg)\\\\=\bigg(\dfrac{11+\sqrt{57}}{4}\bigg)\bigg(\dfrac{11-\sqrt{57}}{4}\bigg)\\\\=\dfrac{121-57}{156} = \dfrac{64}{16} = 4

3 0
2 years ago
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nasty-shy [4]
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2 years ago
Hey can you help me answer this question by giving me the answer?
Leto [7]

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Given a function f(x)=4-2x+6x^{2}.

We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.

Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6a^{2} (By just putting x=a).

f(a+h)==4-2(a+h)+6(a+h)^{2}

=4-2a-2h+6(a^{2} +h^{2} +2ah)

=4-2a-2h+6a^{2} +6h^{2} +12ah

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[f(a+h)-f(a)]/h=[6a^{2} +6h^{2}-2a-2h+12ah-(4-2a+6a^{2} )]/h

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Hence the value of function f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Learn more about function at brainly.com/question/10439235

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Step-by-step explanation:

Because it’s not 4.76% or 10%, and 210% seems drastic. Lemme know if it’s right though.

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