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Studentka2010 [4]
3 years ago
12

3. 3x59x? –15x² +27x

Mathematics
1 answer:
WARRIOR [948]3 years ago
5 0

Answer:

13/10 or 0.3•(599+90)

Step-by-step explanation:

1)33/10•59x-15x^2+27x(x+x=x^2)

2)33/10^2•59-15x^2+27x(factor our 33/10x from the expression)

3)33/10x•(11x-59-10x•5x+10•9)(11x•59=649x)

4)3/10x•(649x-50x+90)(subtract)

answer>>>3/10x or 0.3x•(599+90)

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How many solutions does the equation have, x1 + x2 + x3 = 10 , where x1 , x2, and x3 are non-negative integers?
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Non-negative integers are positive integers or zero.

1. When x_1=0, then there are such possible cases for x_2 and x_3:

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In total 11 solutions for x_1=0.

2. For x_1=1, there are such possible cases for x_2 and x_3:

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4. Add all numbers of solutions:

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Answer: there are 66 possible solutions (with non-negative integer variables)

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