<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
The equation is simply 8s where s is the length of a side. There are 8 sides. You are just adding the length of all 8 sides together to get the perimeter.
Answer:
B
Step-by-step explanation:
Answer:
A = $56,740
Step-by-step explanation:
Use the Compound Amount formula A = P(1 + r)^t. Substitute 0.05 for r and $40,000 for P:
A = $40,000(1 + 0.05)^6
A = $56,740.26, or, rounded off to the nearest dollar,
A = $56,740
Answer:
5.5296
Step-by-step explanation:
to evaluate the expression 4x^4 y^3 we would substitute the value of x and y into it and evaluate. since x = 1/5 and y = 6
4x^4 y^3
4 × x^4 × 4× y³
4 × (1/5)∧4 × 4 × 6³
4× (0.2)∧4 × 4 × 216
4 × 0.0016 × 864
0.0064 × 864
5.5296
