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Marat540 [252]
3 years ago
15

Need the answer..Anyone know?​

Mathematics
1 answer:
hodyreva [135]3 years ago
4 0

You need to show us the figure so we can tell you.

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Sami opens an account with a principal balance of $3,200. The
alina1380 [7]

Answer:

$835.71

Step-by-step explanation:

To solve this problem, we will use the compound interest formula:

A=P(1+\frac{r}{n} )^{nt}

<em>P = initial balance</em>

<em>r = interest rate (decimal)</em>

<em>n = number of times compounded annually</em>

<em>t = time</em>

First, lets change 4.75% into a decimal:

4.75% -> \frac{4.75}{100} -> 0.0475

Now, plug the values into the equation:

A=3,200(1+\frac{0.0475}{1})^{1(5)}

A=4,035.71

Lastly, subtract <em>A </em>from the principal:

4,035.71 - 3,200 = 835.71

The interest earned is $835.71

5 0
3 years ago
The angle whose measure is StartFraction 3 pi Over 4 EndFraction terminates in quadrant II and its reference angle is for StartF
choli [55]

Answer:

I can't tell where the opption's are.... mind spacing them out? thanks :)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find class boundaries, midpoint, and width for the class. 57-61
Bond [772]

Answer:

The answer would be -4

4 0
3 years ago
What is the GCF of 8, 14
Masteriza [31]
The GCF of 8 and 14 is 2 
(2x4 and 2x7)
5 0
3 years ago
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According to national data, 5.1% of burglaries are cleared with arrests. A new detective is assigned to six different burglaries
blagie [28]

Answer:

26.95% probability that at least one of them is cleared with an arrest

Step-by-step explanation:

For each burglary, there are only two possible outcomes. Either it is cleared, or it is not. The probability of a burglary being cleared is independent of other burglaries. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5.1% of burglaries are cleared with arrests.

This means that p = 0.051

A new detective is assigned to six different burglaries.

This means that n = 6

What is the probability that at least one of them is cleared with an arrest?

Either none are cleared, or at least one is. The sum of the probabilities of these events is 100% = 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1)

Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.051)^{0}.(0.949)^{6} = 0.7305

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7305 = 0.2695

26.95% probability that at least one of them is cleared with an arrest

8 0
2 years ago
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