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3 years ago

Need the answer..Anyone know?

Mathematics

1 answer:

hodyreva [135]3 years ago

4 0

You need to show us the figure so we can tell you.

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A 25-foot long ladder is propped against a wall at an angle of 18° with the wall. how high up the wall does the ladder reach? ro

Alecsey [184]

Answer

Find out the how high up the wall does the ladder reach .

To proof

let us assume that the height of the wall be x .

As given

A 25-foot long ladder is propped against a wall at an angle of 18° .

as shown in the diagram given below

By using the trignometric identity

$cos\theta = \frac{Base}{Hypotenuse}$

now

$\theta = 18^{\circ}$

Base = wall height = x

Hypotenuse = 25 foot

Put in the trignometric identity

$cos18^{\circ} = \frac{x}{25}$

$cos18^{\circ} = \bar{0.9510565162}$

x = 23.8 foot ( approx)

Therefore the height of the ladder be 23.8 foot ( approx) .

8 0

3 years ago

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Eight less than the product of 7 and a number is 3. Use the variable w for the unknown number

Tpy6a [65]

W = unknown number
7w - 8 = 3 (product of 7 and a number, w, subtract 8) is 3
7w = 11
w = 11/7

8 0

3 years ago

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Hey pls help worth 30 points

GrogVix [38]

Step 1: Find the slope:

$m = \dfrac{y_2-y_1}{x_2-x_1} = \dfrac{10-6}{6-5} = \dfrac{4}{1} = 4$

Step 2: Set up your equation $y-y_1=m(x-x_1)$ using one of the points.

Using (5,6) we have $y-6 = 4(x-5)$ .

Using (6,10) we have $y-10 = 4(x-6)$

Both of those equations would be correct.

5 0

3 years ago

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The equation of a circle in general form is x2+y2+20x+12y+15=0 . What is the equation of the circle in standard form?

mestny [16]

Answer:

(x)²+(y)²=0

Step-by-step explanation:

6 0

3 years ago

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Help with this question Asap!! I need all the help I can get!

tankabanditka [31]

Answer:

$\large{YES}\ \dfrac{BC}{YZ}=\dfrac{AC}{XY}=\dfrac{AB}{XZ}=\dfrac{2}{1}\\\\\text{and}\ \angle B\cong\angle Z,\ \angle C\cong\angle Y,\ \angle A\cong\angle X$

Step-by-step explanation:

$BC\to ZY\\AB\to XZ\\AC\to XY\\\angle A\to\angle X\\\angle B\to\angle Z\\\angle C\to\angle Y$

$\text{We have:}\\\\\triangle ABC:\ AB=20,\ BC=12,\ AC=18\\\triangle XZY:\ XZ=10,\ YZ=6,\ XY=9\\\\\text{check the ratio:}\\\\\dfrac{AB}{XZ}=\dfrac{20}{10}=2\\\\\dfrac{BC}{YZ}=\dfrac{12}{6}=2\\\\\dfrac{AC}{XY}=\dfrac{18}{9}=2\\\\\text{CORRECT :)}\\\\\angle B\cong\angle Z,\ \angle C\cong\angle Y\\\\\text{We know that: The sum of the acute angles in a right triangle is}\ 90^o.\\\\m\angle B+m\angle A=90^o\ \text{and}\ m\angle Z+m\angle X=90^o$

$\text{We know}\ m\angle B=m\angle Z\to \ m\angle A=m\angle X.\\\text{therefore}\ \angle A\cong\angle X$

5 0

3 years ago

Need the answer..Anyone know?​

Need the answer..Anyone know?