Mason currently pas $420 per month in rent. the contract on his apartment sates that his rent will increase by 6% next year.

The author drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 200 times. Here are the observed

algol [13]

Answer:

$\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860$

$p_v = P(\chi^2_{5} >5.860)=0.32$

Since the p value is higher than the significance level assumed 0.05 we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we can assume that we have equally like results.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Number: 1, 2 , 3 , 4 , 5 ,6

Frequency: 27, 31, 42, 40, 28, 32

We need to conduct a chi square test in order to check the following hypothesis:

H0: The outcomes are equally likely.

H1: The outcomes are not equally likely.

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The observed values are given:

$O_{1}=27$ $O_{2}=31$

$O_{3}=42$ $O_{4}=40$

$O_{5}=28$ $O_{6}=32$

The expected values are given by:

$E_{1} =\frac{1}{6}*200=33.33$ $E_{2} =\frac{1}{6}*200=33.33$

$E_{3} =\frac{1}{6}*200=33.33$ $E_{4} =\frac{1}{6}*200=33.33$

$E_{5} =\frac{1}{6}*200=33.33$ $E_{6} =\frac{1}{6}*200=33.33$

And now we can calculate the statistic:

$\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860$

Now we can calculate the degrees of freedom for the statistic given by:

$df=Categories-1=6-1=5$

And we can calculate the p value given by:

$p_v = P(\chi^2_{5} >5.860)=0.32$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(5.860,5,TRUE)"

Since the p value is higher than the significance level assumed 0.05 we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we can assume that we have equally like results.

4 0

3 years ago

What's the sum of two integers with different signs is 8

dem82 [27]

16 + (-8) = 8 <== here is one
16 - 8 = 8
8 = 8 (correct)

-12 + 20 = 8 <== and another
11 + (- 3) = 8 <== and another

7 0

3 years ago

Help plzzz!!! Find a a= 12 a= 10 a= 1 a= 29

RideAnS [48]

Answer:

a=22.6549

Step-by-step explanation:

Calculated based on 2 given angles and 1 given side.

∠C = 180° - A - B = 0.99484 rad = 57°

a = c·sin(A)/sin(C) = 22.6549

b = c·sin(B)/sin(C) = 12.33874

3 0

3 years ago

PLEASE ASAP FOR FULL POINTS

NARA [144]

It’s between B or C
Sorry if I’m wrong

3 0

3 years ago

Determine whether the formula describes y as a function of x. Explain your reasoning.. . y = -x

Alex17521 [72]

The given formula above, y = -x, is a sample of a function. A function is an equation that would give only one value of y for every value of x. This is the same as saying that exactly one output is set by each input. If we take x = -1, the value of y is 1 and nothing else.

7 0

3 years ago