Can you elaborate? because i don’t understand what topic
2x^2+2x-4=2(2x^2+2x-4)/2=[2(2x^2)+2(2x)-2(4)]/2=[2^2x^2+2(2x)-8]/2
2x^2+2x-4=[(2x)^2+2(2x)-8]/2=(2x+4)(2x-2)/2=2(2x/2+4/2)2(2x/2-2/2)/2
2x^2+2x-4=2(x+2)(x-1)
Answer: Option B. 2(x+2)(x-1)
I don’t even know sorry I will try and help out next time
There are 6 faces in this prism. Each pair of opposite faces is two congruent faces.
The front and back faces have dimensions x by x + 4.
The right and left faces have dimensions x + 2 by x + 4.
The top and bottom faces have dimensions x by x + 2.
Let's find the area of each different face.
Front & back:
A = LW = x(x + 4) = x^2 + 4x
Right and left:
A = LW = (x + 2)(x + 4) = x^2 + 4x + 2x + 8 = x^2 + 6x + 8
Top & bottom:
A = LW = x(x + 2) = x^2 + 2x
Now we add the three areas:
x^2 + 4x + x^2 + 6x + 8 + x^2 + 2x =
=3x^2 + 12x + 8
The polynomial above is the sum of the areas of three different faces.
Each of the three different faces has a congruent opposite face with the same area, so we double this area to find the total surface area of all 6 faces.
2(3x^2 + 12x + 8) = 6x^2 + 24x + 16
The answer is option A.
Divide by a 100. that's it