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OLEGan [10]
2 years ago
7

What is the shaded portion of the figure?

Mathematics
1 answer:
Tema [17]2 years ago
3 0

Answer:

D

Step-by-step explanation:

Area of Part of a Circle = (θ/360)\pi r^{2}

We first find the area of CAB first.

Radius of CAB = AB = 6cm

θ  = 112

Area of CAB = \frac{112}{360} \pi (6)^{2} \\=\frac{56}{5} \pi cm^{2}

Next we will find the area of FAE.

Radius of FAE = AE = 4cm

Area of FAE = \frac{112}{360} \pi (4)^{2} \\=\frac{224}{45} \pi cm^{2}

Lastly,

Area of Shaded Region = Area of CAB - Area of FAE

= \frac{56}{5} \pi -\frac{224}{45}\pi \\=\frac{56}{9} \pi cm^{2}

Therefore the answer is D.

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Ariane feeds her kitten kkk grams of food 222 times in the morning and 222 times in the evening. She feeds her dog ddd grams of
ANTONII [103]

Answer: The required expression is,

4k + 2d

Step-by-step explanation:

Given,

She feeds her kitten k gram of food,

She feeds 2 times in the morning,

⇒ Food fed in morning = 2k,

Also, she feeds 2 times in the evening,

⇒ Food fed in evening = 2k,

So, the total food she gives to her kitten = 2k + 2k = 4k,

Now, She feeds her dog d gram of food,

She feeds 1 times in the morning,

⇒ Food fed in morning = d,

Also, she feeds 2 times in the evening,

⇒ Food fed in evening = d,

So, the total food she gives to her dog = d + d = 2d,

Hence, the total food she feeds to her animal in a day = 4 k + 2 d

6 0
3 years ago
From Andys house to Billys hometown you can travel by 3 roads. And to get from Billys hometown to Willies's house you can travel
Rom4ik [11]

Andy to get to Willie's house = 15 ways

Andy to get to Willie's house = 45 ways

<h3>How to determine the ways</h3>

From the information given, we have that from

Andy's house to Billy's  hometown = 3 roads

Billy's hometown to Willies house = 5 ways

To travel from Andy's house to Willies house, we should multiply the number of ways

= 3 × 5

= 15 ways

Dan's ranch to Andy's house = 1 road

To Willie's house = 2 roads

For Andy to get to Willie's house, we have;

= 3 × 15

= 45 ways

Learn more about word problems here:

brainly.com/question/1781657

#SPJ1

3 0
2 years ago
Graph the system of inequalities. Then use your graph to identify the point that represents a solution to the system. x &gt; 4 y
8_murik_8 [283]
The first thing you should do in that case is to graph both lines.
 Once graphed you must see which region of the Cartesian plane they meet their respective inequalities.
 The solution of the inequation system is the shaded region shown.
 The point sought is
 P = (5, -2)
 answer
<span> (5, –2)</span>

7 0
3 years ago
The table below represents a linear relationship.
Ede4ka [16]

Answer:i think it 3

Step-by-step explanation:

5 0
3 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
3 years ago
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