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3 years ago

X^2-5x=-4 . I need to find the zeroes

1 answer:

4 0

The zeros of a quadratic equation are equal to the x-intercepts of its graph. In other words, you must find the x-value that causes the expression to equal zero. Start by adding 4 to both sides of the equation:

X² - 5x + 4 = 0

Factor the equation:

(x - 1)(x - 4) = 0

Now calculate each piece separately, starting with the first one:

x - 1 = 0

Add 1 to both sides of the equation:

x = 1

We have proven that x = 1. Now calculate the second piece:

x - 4 = 0

Add 4 to both sides of the equation:

x = 4

We have proven that x = 4. Consequently, we have proven that (x = 1) and (x = 4) are the two zeros of this quadratic equation.

I hope this helps!

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Answer:

y = -2x - 3

Step-by-step explanation:

y = mx + b

-15 = -2(6) + b

-15 = -12 + b

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Find the x-coordinates of the points where the graph crosses the x-axis:

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Answer:

29. (5,0) and (-7/2,0)

30. (-1,0) and (5/7,0)

Step-by-step explanation:

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See the attached graph.

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2 years ago

Most US adults have social ties with a large number of people, including friends, family, co-workers, and other acquaintances. I

xxTIMURxx [149]

Answer:

$t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971$

$p_v =2*P(t_{(1699)}>1.971)=0.049$

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=669$ represent the sample mean

$s=732$ represent the sample standard deviation

$n=1700$ sample size

$\mu_o =68$ represent the value that we want to test

$\alpha=0.$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:

Null hypothesis: $\mu = 634$

Alternative hypothesis: $\mu \neq 634$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=1700-1=1699$

Since is a two sided test the p value would be:

$p_v =2*P(t_{(1699)}>1.971)=0.049$

Conclusion

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3 years ago

Find the first four nonzero terms in a power series expansion about xequals0 for the solution to the given initial value problem

IgorC [24]

Answer:

The first four terms are;

w(x)= 4 + 2x² - ⁵/₆x⁴+ ¹¹/₃₆x⁶ +......

Step-by-step Explanation:

This is the interpretation of the question

w″ + 3xw′ -w=0

W(0)=4

W′(0)=0

CHECK THE ATTACHMENT FOR STEP BY STEP EXPLANATION

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