Write the equation of the line that passes through the point (3,-1) and has a slope of 2

lawyer [7]

Answer:

1/6

Step-by-step explanation:

1/6 + 1/6 + 1/6 + 1/6 = 4/6. A unit fraction has a numerator of 1 so since 4 is the numerator in 4/6 You should add 1/6 four times.

Hope this helps!

Brain-List?

3 0

2 years ago

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A company determined that the marginal cost, C' (x )of producing the xth unit of a product is given by C' (x )= x^3- 6x. Find t

Rashid [163]

Answer:

$C(x) = \frac{x^4}{4}-3x^2+3,000$

Step-by-step explanation:

The marginal cost function, C'(x), is the derivate of the cost function, C(x).

Therefore, we can obtain the cost function by finding the integral of the marginal cost function:

$C(x) = \int\ {C'(x)} \, dx \\C(x) = \int\ {(x^3-6x)} \, dx \\C(x) = \frac{1}{4} x^4-3x^2+a$

Where 'a' is a constant and represents fixed costs. If fixed costs are $3,000, the cost function is:

$C(x) = \frac{x^4}{4}-3x^2+3,000$

3 0

2 years ago

I only need 12 and 17, first good response i will give brainliest please i’m desperate

Mumz [18]

Answer:

$\textsf{12.} \quad y = 6x - 5$

$\textsf{17.} \quad y=-\dfrac{1}{4}x-2$

Step-by-step explanation:

<h3><u>Question 12</u></h3>

Find the slope of the line by substituting two points from the given table into the slope formula.

<u>Define the points</u>:

Let (x₁, y₁) = (2, 7)
Let (x₂, y₂) = (3, 13)

$\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{13-7}{3-2}=\dfrac{6}{1}=6$

Substitute the found slope and point (2, 7) into the point-slope formula to create an equation of the line:

$\implies y-y_1=m(x-x_1)$

$\implies y-7=6(x-2)$

$\implies y-7=6x-12$

$\implies y=6x-5$

<h3><u>Question 17</u></h3>

Given:

f(4) = 3
f(0) = -2

Therefore, two points on the line are:

(4, -3)
(0, -2)

The y-intercept is the y-value when x = 0.

Therefore, the y-intercept of the line is -2.

$\boxed{\begin{minipage}{6.3 cm}\underline{Slope-intercept form of a linear equation}\\\\$y=mx+b$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $b$ is the $y$-intercept.\\\end{minipage}}$

Substitute the y-intercept and the point (4, 3) into the slope-intercept formula and solve for <em>m</em> to find the slope:

$\implies y=mx+b$

$\implies -3=m(4)-2$

$\implies -1=4m$

$\implies m=-\dfrac{1}{4}$

Therefore, the equation of the line is:

$y=-\dfrac{1}{4}x-2$

7 0

6 months ago

The team first experiments with changing the position of the curved pit. In the computer program, the vertex begins on the origi

Advocard [28]

Answer:

Step-by-step explanation:

This question is incomplete; find the complete question in the attachment.

Given curve is modeled by the quadratic equation,

y = x²

If the curved pit is shifted 2 units down,

Equation of the translated curve will be,

y = x² - 2

If the curved pit is translated (shifted) by 2 units left,

Equation of the new curve will be,

y = (x + 2)²

If the curved pit is shifted by 2 units right,

Equation of the translated curve will be,

y = (x - 2)²

If the curved pit is shifted 2 units up,

Equation of the translated curve will be,

y = x² + 2

6 0

2 years ago

Explain why vertical lines are a special case in the definition of parallel lines.

Nookie1986 [14]

Answer:

A vertical line has an infinite or undefined slope since the denominator is zero.

Step-by-step explanation:

Parallel lines by definition refers to lines that never intersect or meet since they have identical slopes. The slope of line is defined as;

(change in y)/(change in x)

For a vertical line, the y values are changing while the x values remain constant. The slope of this line will thus have a zero value in the denominator implying that its slope will not defined or will be infinity.

6 0

2 years ago

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