Question

Help … fr …. D: D: D: D:

Answer 1

Step-by-step explanation:

Let x be mixture x liters and y be mixture y liters.

We need a total of 4 liters so

$x + y = 4$

Mixture x is 20% saline solution

Mixture Y is a 10% saline solution

4 liters of a 15% saline solution is 60% saline solution.

$.20x + .10y = 0.6$

So a is the system of equations,

Using Elimination, eliminate the variable x.

$- 5(.20x + .10y) = 0.6$

$( - x - .50y) = - 3$

Add to the first system.

$0.50y = 1$

$y = 2$

Plug this into the of system of equations, to find x

$x + 2 = 4$

$x = 2$

So our solution is (2,2) We would need 2 liters of Mixture X and 2 liters of Mixture Y