All categories

3 years ago

Suppose an isosceles triangle ABC has A = 45° and b = c = 4. What is the length of a2? A.22.63

Mathematics

1 answer:

weeeeeb [17]3 years ago

3 0

Since b = c, the angles B and C also equal

so you get
180 - 45 = 135
135/2 = =67.5 for each angle

now we know 2 sides and all 3 angles, use the law of sines to find a

b/sin B = a/sin A

4/(sin 67.5) = a/(sin 45)

a = 4(sin 45)/(sin 67.5)

a^2 = (4(sin 45)/(sin 67.5))^2

a^2 = 9.37

Answer is C

You might be interested in

Johnny has graded 20% of his 150 students papers how many papers does he still need to finish grading ?

LiRa [457]

The correct answer is 120 papers.

4 0

3 years ago

Read 2 more answers

The graph shown below expresses a radical function that can be written in the form f(x)= a(x + k)^1/n +C. What does the graph te

MAXImum [283]

Answer:

C. <em>c</em> is less than zero

Step-by-step explanation:

The parent radical function y=x^(1/n) has its point of inflection at the origin. The graph shows that point of inflection has been translated left and down.

<h3>Function transformation</h3>

The transformation of the parent function y=x^(1/n) into the function ...

f(x) = a(x +k)^(1/n) +c

represents the following transformations:

vertical scaling by a factor of 'a'
left shift by k units
up shift by c units

<h3>Application</h3>

The location of the inflection point at (-3, -4) indicates it has been shifted left 3 units, and down 4 units. In the transformed function equation, this means ...

k = 3
c = -4

The graph says the value of c is less than zero.

<em>Additional comment</em>

Apparently, the value of 'a' is 2, and the value of n is 3. The equation of the graph seems to be ...

f(x) = 2(x +3)^(1/3) -4

8 0

2 years ago

Can someone pleaseee help me!!

Cloud [144]

Answer:

121

Step-by-step explanation:

180°-74° = 106°

106°= x-15°

106+15= X

x= 121

(correct me if im wrong plz)

8 0

3 years ago

15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.

Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = $30C5 = \frac{30 !}{(30-5)!5!} \\$

$30C5 = 142506$ ways

Number of ways of selecting 5 good bulbs from 26 bulbs = $26C5 = \frac{26 !}{(26-5)!5!} \\$

$26C5 = 65780$ ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = $\frac{26C4 * 4C1}{30C5}$

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) = $\frac{26C3 * 4C2}{30C5}$

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) + Pr(2 defective) + Pr(3 defective) + Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) = $\frac{26C2 * 4C3}{30C5}$

Pr(3 defective) = 0.009

Pr(4 defective) = $\frac{26C1 * 4C4}{30C5}$

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0

3 years ago

6.- Find the area under the standard normal distribution: to the left of z=-1.55.

Kisachek [45]

Answer:

$P(z$

Step-by-step explanation:

For this case we want to find this probability:

$P(z$

Because they want the area to the left of the value. We need to remember that the normal standard distribution have a mean of 0 and a deviation of 1.

We can use the following excel code: =NORM.DIST(-1.55,0,1,TRUE)

And we got:

$P(z$

The other possibility is use the normal standard table and we got a similar result.

5 0

3 years ago