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alexgriva [62]
3 years ago
10

Suppose an isosceles triangle ABC has A = 45° and b = c = 4. What is the length of a2? A.22.63

Mathematics
1 answer:
weeeeeb [17]3 years ago
3 0

Since b = c, the angles B and C also equal

 so you get
180 - 45 = 135
135/2 = =67.5 for each angle

now we know 2 sides and all 3 angles, use the law of sines to find a

b/sin B = a/sin A

4/(sin 67.5) = a/(sin 45)

a = 4(sin 45)/(sin 67.5)

a^2 = (4(sin 45)/(sin 67.5))^2

a^2 = 9.37

 Answer is C

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sertanlavr [38]
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7| 1 9 8 6

Step 2. <span>Calculate 19 ÷ 7, which is 2 with a remainder of 5.

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Step 4. <span>Calculate 58 ÷ 7, which is 8 with a remainder of 2.

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Step 5. <span>Bring down 6, so that 26 is large enough to be divided by 7.

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Step 6. Calculate 26 ÷ 7, which is 3 with a remainder of 5.
   
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Step 7. <span>Therefore, 1986 ÷ 7 = 283 with a remainder of 5.

823 With a remainder of 5

Done!

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