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zepelin [54]
3 years ago
5

*1 A car is driving away from a crosswalk. The distance d (in feet) of the car from the crosswalk t

Mathematics
1 answer:
antoniya [11.8K]3 years ago
7 0

Answer:

The change in the car's distance is 8 feet

Step-by-step explanation:

* Lets explain how to solve the problem

- A car is driving away from a crosswalk

- The distance d (in feet) of the car from the crosswalk t  seconds

  since the car started moving is given by the formula d = t² + 3.5

- The time increasing from 1 second to 3 seconds

- We need to now the change of the car's distance from the crosswalk

∵ The equation of the distance is d = t² + 3.5

∵ The time is 1 second

∴ d = (1)² + 3.5

∴ d = 1 + 3.5 = 4.5 feet

∵ The time is 3 seconds

∴ d = (3)² + 3.5

∴ d = 9 + 3.5 = 12.5 feet

∵ The change of the distance = d of 3 sec - d of 1 sec

∵ d of 3 sec = 12.5 feet

∵ d of 1 sec = 4.5 feet

∴ The change of the distance = 12.5 - 4.5 = 8 feet

∴ The change in the car's distance is 8 feet

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An above-ground swimming pool is leaking. The function h(d) = 48 - 1. 5d gives the height of the water in the pool in inches d d
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B) 40.5 in : height of the water after 5 days

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Step-by-step explanation:

h(d) = 48 - 1. 5d

A)  

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