Answer:
The third choice.
Explanation:
It is near the Orion Arm and extremely far from the center. Although I don't know about the "tip"
Answer: SPORES are defined as haploid (1n) cells which develops into gametophytes.
Gametophytes inturn produce either haploid (1n) male or females GAMETES that can fuse to form diploid ZYGOTES.
This basically explains what goes on in Meiosis.
Answer:
Red blood cells and blood plasma do not contain DNA. Red blood cells don't have the DNA containing nucleus and mitochondria. Only white blood cells in blood contain DNA. With blood donation, usually most of the white blood cells are filtered out.
Explanation:
because red blood cells don't have the DNA containing nucleus and mitochondria
Half life formula
The number of unstable nuclei remaining after time t can be determined according to this equation:
N(t) = N(0) * 0.5^(t/T)
where:
N(t) is the remaining quantity of a substance after time t has elapsed.
N(0) is the initial quantity of this substance.
T is the half-life.
It is also possible to determine the remaining quantity of a substance using a few other parameters:
N(t) = N(0) * e^(-t/τ)
N(t) = N(0) * e^(-λt)
τ is the mean lifetime - the average amount of time a nucleus remains intact.
λ is the decay constant (rate of decay).
All three of the parameters characterizing a substance's radioactivity are related in the following way:
T = ln(2)/λ = ln(2)*τ
How to calculate the half life
Determine the initial amount of a substance. For example, N(0) = 2.5 kg.
Determine the final amount of a substance - for instance, N(t) = 2.1 kg.
Measure how long it took for that amount of material to decay. In our experiment, we observed that it took 5 minutes.
Input these values into our half life calculator. It will compute a result for you instantaneously - in this case, the half life is equal to 19.88 minutes.
If you are not certain that our calculator returned the correct result, you can always check it using the half life formula.
Answer:
B
Explanation:
Oxygen is the final acceptor of electrons in the process of oxidative phosphorylation. Without oxygen, the process becomes jammed with electrons.
