Answer:
0.1348 = 13.48% probability that 3 of them entered a profession closely related to their college major.
Step-by-step explanation:
For each graduate, there are only two possible outcomes. Either they entered a profession closely related to their college major, or they did not. The probability of a graduate entering a profession closely related to their college major is independent of other graduates. This, coupled with the fact that they are chosen with replacement, means that we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
53% reported that they entered a profession closely related to their college major.
This means that ![p = 0.53](https://tex.z-dn.net/?f=p%20%3D%200.53)
9 of those survey subjects are randomly selected
This means that ![n = 9](https://tex.z-dn.net/?f=n%20%3D%209)
What is the probability that 3 of them entered a profession closely related to their college major?
This is P(X = 3).
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 9) = C_{9,3}.(0.53)^{3}.(0.47)^{6} = 0.1348](https://tex.z-dn.net/?f=P%28X%20%3D%209%29%20%3D%20C_%7B9%2C3%7D.%280.53%29%5E%7B3%7D.%280.47%29%5E%7B6%7D%20%3D%200.1348)
0.1348 = 13.48% probability that 3 of them entered a profession closely related to their college major.
The sign of "b" on the numerator should be negative. So we conclude that the correct option is false.
<h3>Is the equation in the image correct or incorrect?</h3>
For a quadratic equation of the form:
![y = a*x^2 + b*x + c](https://tex.z-dn.net/?f=y%20%3D%20a%2Ax%5E2%20%2B%20b%2Ax%20%2B%20c)
By using the Bhaskara's formula, the solutions of the equation:
![0 = a*x^2 + b*x + c](https://tex.z-dn.net/?f=0%20%3D%20a%2Ax%5E2%20%2B%20b%2Ax%20%2B%20c)
Are given by the formula:
![x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E2%20-%204ac%7D%20%7D%7B2a%7D)
Notice that the sign of the first term on the numerator should be negative, while on the image it is positive.
So the equation shown in the image is incorrect.
If you want to learn more about quadratic equations:
brainly.com/question/1214333
#SPJ1
The answer is 1.5 or 1 1/2.
here is the how you get this answer.
1: Cross Multiply (1.2)(60)=x
2: divide x by 48
3: you should get 1.5 or 3/2
BTW x is equal to 72
Answer:
Answer is on the pic
Step-by-step explanation:
I hope it's helpful!
The answer would be 58 degrees. You have to add the measure of R and P, and since a triangle is a total of 180 degrees, you subtract the sum and R and P from 180 and get your answer. Hope this helps!