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gizmo_the_mogwai [7]
1 year ago
11

13. In A ABC, if m BF is an angle bisector, find m

Mathematics
1 answer:
Tresset [83]1 year ago
4 0

If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.

Given that m∠ABF=41° and BF is an angle bisector.

We are required to find the angle m∠BCE if BF is an angle bisector.

Angle bisector basically divides an angle into two parts.

If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.

In this way ∠ABC=2*∠ABF

∠ABC=2*41

=82°

In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.

∠BCE+∠CEB+EBC=180  (Sum of all the angles in a triangle is 180°)

∠BCE+90+82=180

∠BCE=180-172

∠BCE=8°

Hence if BF is an angle bisector then angle m∠BCE=8°.

Learn more about angles at brainly.com/question/25716982

#SPJ1

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3/2

<em>Step One:</em> 1 3/8, transform the number into a improper fraction:

  1. To have a mixed number in to a improper fraction, you need to use            addition and multiplication.  For 1 3/8, We first multiply the denominator (8, also know to be the bottom number of the fraction) to the whole number (1).  8x1= 8
  2. NOTE: The original denominator (8) will be use for are improper, again playing as the denominator, we only multiply the denominator for the numerator (which is the top number of a fraction).
  3. After multiplying, we'll add are product with the numerator (3) for the process. 8+3= 12
  4. Now we have both numerator and denominator for 1 3/8, we can create the improper fraction. 12 as the numerator and 8 as the denominator. 12/8
  5. We still need to simplify the number. To that, we need the biggest whole number, or rather I call it the lowest number, that can be divide both in 12 and 8.
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