Answer:
the positive slope of the asymptote = 5
Step-by-step explanation:
Given that:

Using the standard form of the equation:

where:
(h,k) are the center of the hyperbola.
and the y term is in front of the x term indicating that the hyperbola opens up and down.
a = distance that indicates how far above and below of the center the vertices of the hyperbola are.
For the above standard equation; the equation for the asymptote is:

where;
is the slope
From above;
(h,k) = 11, 100
= 100
a = 
a = 10

b = 
b = 2


y = 5x-53 , -5x -57
Since we are to find the positive slope of the asymptote: we have
to be the slope in the equation 
= 
= 5
Thus, the positive slope of the asymptote = 5
Answer:
P = 1.21
Step-by-step explanation:
P = original price by/per pound
3 (P+.75) = 5.88
5.88/3 = 1.96
P = 1.21
3/5x+2/5=7
-2/5 -2/5
3/5x = 6 3/5
/3/5. /3/5
X=11
From the given volume, we know that the ratio is:
![\text {Ratio of yellow eraser to white eraser = } \sqrt[3]{ \dfrac{16}{2} }](https://tex.z-dn.net/?f=%5Ctext%20%7BRatio%20of%20yellow%20eraser%20to%20white%20eraser%20%3D%20%7D%20%20%5Csqrt%5B3%5D%7B%20%5Cdfrac%7B16%7D%7B2%7D%20%7D%20)
From the given area, we know that the ratio is:

Equate the two ratio and solve for x:
![\sqrt[3]{ \dfrac{16}{2} } = \sqrt{ \dfrac{52}{x} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%20%5Cdfrac%7B16%7D%7B2%7D%20%7D%20%20%3D%20%5Csqrt%7B%20%5Cdfrac%7B52%7D%7Bx%7D%20%7D%20)
Cube both sides:

Square both sides:

Simplify each term:

Cross multiply:

Divide both sides by 256:

Cube root both sides: