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storchak [24]
2 years ago
9

What statement is true for f(x) = 3.2^x?

Mathematics
1 answer:
goblinko [34]2 years ago
7 0

Answer:

Step-by-step explanation:

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What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .
VladimirAG [237]

Answer:

the  positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

\frac{(y+11)^2}{100} -\frac{(x-6)^2}{4} =1

Using the standard form of the equation:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}= 1

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term  indicating that the  hyperbola opens up and down.

a = distance that indicates  how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

y = \pm \frac{a}{b} (x-h)+k

where;

\frac{a}{b} is the slope

From above;

(h,k) = 11, 100

a^2 = 100

a = \sqrt{100}

a = 10

b^2 =4

b = \sqrt{4}

b = 2

y = \pm \frac{10}{2} (x-11)+2

y = \pm 5 (x-11)+2

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have  

\frac{a}{b} to be  the slope in the equation  y = \pm \frac{10}{2} (y-11)+2

\frac{a}{b}  = \frac{10}{2}

\frac{a}{b}  = 5

Thus, the  positive slope of the asymptote = 5

8 0
3 years ago
In winter, the price of apples suddenly went up by $0.75 per pound. Sam bought 3 pounds of apples at the new price for a total o
juin [17]

Answer:

P = 1.21

Step-by-step explanation:

P = original price by/per pound

3 (P+.75) = 5.88

5.88/3 = 1.96

P = 1.21

7 0
4 years ago
Show work pls, WILL GIVE BRAINLIEST <br> (3/5)x+2/5=7
Dominik [7]
3/5x+2/5=7
-2/5 -2/5
3/5x = 6 3/5
/3/5. /3/5
X=11
8 0
3 years ago
How do you simplify this with no negative exponents ?<br><br> (2x^-2 y^3) (3x^3 y^3)
mafiozo [28]

Answer:

6xy with the power of 6

8 0
3 years ago
Does anyone know the surface area for this problem. if so i will mark brainliest.
sveticcg [70]

From the given volume, we know that the ratio is:
\text {Ratio of yellow eraser to white eraser = }  \sqrt[3]{ \dfrac{16}{2} }

From the given area, we know that the ratio is:
\text {Ratio of yellow eraser to white eraser = }  \sqrt{ \dfrac{52}{x} }

Equate the two ratio and solve for x:
\sqrt[3]{ \dfrac{16}{2} }  = \sqrt{ \dfrac{52}{x} }

Cube both sides:
\dfrac{16}{2} = \bigg(\sqrt{ \dfrac{52}{x} }\bigg)^3

Square both sides:
\bigg(\dfrac{16}{2} \bigg)^2 = \bigg( \dfrac{52}{x}  }\bigg)^3

Simplify each term:
\dfrac{16^2}{2^2} = \dfrac{52^3}{x^3}

Cross multiply:
256x^3 = 562432

Divide both sides by 256:
x^3 = 2197

Cube root both sides:
x = 13

7 0
4 years ago
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