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ella [17]
2 years ago
10

What is the solution for w in the equation?

Mathematics
1 answer:
OlgaM077 [116]2 years ago
3 0

Answer:

B. 2

w=2

Step-by-step explanation:

hope this helps!

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julia-pushkina [17]

Answer:

f, it isnt doing anything as going up in units of water

Step-by-step explanation:

7 0
3 years ago
If b = 3, then 3x + y = 1 and bx - y = 3 are parallel.<br> True or <br> False ...?
Ulleksa [173]
I am absolutely sure that the task <span> b = 3, then 3x + y = 1 and bx - y = 3 is NOT parallel, which means that the statement represented above is FALSE.
To make sure you can check it using : </span>y=-3x+1&#10;&#10;y=3x-3 Hope now it's obvious. Regards!
4 0
4 years ago
Find the value of x. The diagram is not to scale. (Unit<br> (2x +10)<br> 1489<br> 1120
Elden [556K]

x is 12 as 2 plus 10 so that you can write the value or tell the value

8 0
3 years ago
What expressions equivalent to 25c+15 ? ( more than one answer )
grin007 [14]

Answer:

The only one that looks familiar is B sorry >-<

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Let R be the region in the first quadrant bounded by the graphs of y =x^2 and y=2x, as shown in the figure above. The region R i
Kobotan [32]

Answer:

The area between the two functions is approximately 1.333 units.

Step-by-step explanation:

If I understand your question correctly, you're looking for the area surrounded by the the line y = 2x and the parabola y = x², (as shown in the attached image).

To do this, we just need to take the integral of y = x², and subtract that from the area under y = 2x, within that range.

First we need to find where they intersect:

2x = x²

2 = x

So they intersect at (2, 4) and (0, 0)

Now we simply need to take the integrals of each, subtracting the parabola from the line (as the parabola will have lower values in that range):

a = \int\limits^2_0 {2x} \, dx - \int\limits^2_0 {x^2} \, dx\\\\a = x^2\left \{ {{x=2} \atop {x=0}} \right - \frac{x^3}{3}\left \{ {{x=2} \atop {x=0}} \right\\\\a = (2^2 - 0^2) - (\frac{2^3}{3} - \frac{0^3}{3})\\\\a = 2^2 - \frac{2^3}{3}\\a = 4 - 8/3\\a \approx 1.333

So the correct answer is C, the area between the two functions is 4/3 units.

3 0
3 years ago
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