I believe it is the first one but I might be wrong.
Answer:
Step-by-step explanation:
Given that the television show Degenerate Housewives has been successful for many years. That show recently had a share of 18, meaning that among the TV sets in use, 18% were tuned to Degenerate Housewives.
Each household is independent of the other and there two outcomes.
X no of households that are tuned to Degenerate Housewives. is Bin (12, 0.18)
the probability that none of the households are tuned to Degenerate Housewives. P(none) =_______0.0924_____
the probability that at least one household is tuned to Degenerate Housewives. P(at least one) = ____1-0.0924 = 0.9076______
the probability that at most one household is tuned to Degenerate Housewives. P(at most one) = _____0.3359______
If at most one household is tuned to Degenerate Housewives, does it appear that the 18% share value is wrong? (Hint: Is the occurrence of at most one household tuned to Degenerate Housewives unusual?)
No 33% is not unusual.
Answer:
sometimes
Step-by-step explanation:
We can consider the example of a cuboid.
It is a rectangular solid whose all faces are made of rectangles.
But if we will consider a example of cube; which is also a kind of rectangular solid whose all faces are made up of square.
so we can get some solids whose faces are other than squares as well and some whose faces are squares.
Hence, we could say that:
The faces of a rectangular solid are sometimes square.
So he knows there are definitely 66 trouts as he caught and tagged them.
The next day he caught 52, but 13 of them were already tagged, so were part of the number of trout he caught before.
So he can expect that:
66+(52-13)= 105 trout are in the lake
