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My name is Ann [436]
3 years ago
7

Can anybody help me solve these problems? My teacher had a answer key up for us to check our answers but I have no idea where to

start.

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
7 0

Answer:

f = 59

g = 59

Step-by-step explanation:

f = 180 - 121

f = 59

g = 180 - 121

g = 59

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4 years ago
Based on the figure, which statement provides enough information to conclude that line ris
GREYUIT [131]

Answer:

m<6 = 90°

Step-by-step explanation:

If lines are perpendicular, the angles form by their intersection measure 90°.

Answer: m<6 = 90°

4 0
2 years ago
14 – (2y + 5) = -2y + 9
patriot [66]

Answer:

The answer is all real numbers

Step-by-step explanation:

Simpify both sides of the equation: 14−(2y+5)=−2y+9

14+−1(2y+5)=−2y+9(Distribute the Negative Sign)

14+−1(2y)+(−1)(5)=−2y+9

14+−2y+−5=−2y+9

(−2y)+(14+−5)=−2y+9(Combine Like Terms)

−2y+9=−2y+9

−2y+9=−2y+9

Then add 2y to each side. −2y+9+2y=−2y+9+2y

9=9. Then subtract 9 from each side. 9-9=9-9=0. That means that all real numbers is the answer.

8 0
4 years ago
Read 2 more answers
suppose you buy 158,000 home. you found out the bank offers 30 year loan at 6.5% APR. What will he your monthly payment
serg [7]

Answer: $998.67

Step-by-step explanation:

M = P[r(1+r)^n/((1+r)^n)-1)]

This does not include taxes, insurance, or PMI

8 0
3 years ago
two leaky containers are filling with water. water enters container a at a rate of 2/3 cup per 1/2 minute and leaks out at a rat
kipiarov [429]

container B needs to be filled faster in order for both containers to gain the same amount of water per minute , and by 1/6 water per minute .

<u>Step-by-step explanation:</u>

Here we have , two leaky containers are filling with water. water enters container a at a rate of 2/3 cup per 1/2 minute and leaks out at a rate of 1/4 cup per 3/4 minute. water enters container b at a rate of 3/4 cup per 1/2 minute and leaks out at a rate of 1/2 cup per 3/4 minute. We need to find which container needs to be filled faster in order for both containers to gain the same amount of water per minute . Let's find out:

Rate of Filling container A:

⇒ \frac{\frac{2}{3} }{\frac{1}{2} }

⇒ \frac{2}{3} (2) = \frac{4}{3}

Rate of leaking Container A:

⇒ \frac{\frac{1}{4} }{\frac{3}{4} }

⇒ \frac{1}{4} (\frac{4}{3}) = \frac{1}{3}

Amount of water in Container A in one minute :

⇒ \frac{4}{3}  - \frac{1}{3} = 1

No , following same for Container B

Rate of Filling container B:

⇒ \frac{\frac{3}{4} }{\frac{1}{2} }

⇒ \frac{3}{4} (\frac{2}{1}) = \frac{3}{2}

Rate of leaking Container B:

⇒ \frac{\frac{1}{2} }{\frac{3}{4} }

⇒ \frac{1}{2} (\frac{4}{3}) = \frac{2}{3}

Amount of water in Container B in one minute :

⇒ \frac{3}{2}  - \frac{2}{3} = \frac{5}{6}

Since , Rate of water per minute in container A is 1 and , Rate of water per minute in container B is 5/6 , container A fills faster by container B by

⇒ 1-\frac{5}{6} = \frac{1}{6}

Therefore , container B needs to be filled faster in order for both containers to gain the same amount of water per minute , and by 1/6 water per minute .

8 0
3 years ago
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