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Molodets [167]
1 year ago
12

Question 31 (5 points) Find the area of the shaded portion if we know the outer circle has a diameter of 4 m and the inner circl

e has a diameter of 1.5 m. O O 10.8 m2 O 12.6 m2 O 43.2 m2 O 1.8 m2

Mathematics
1 answer:
Vadim26 [7]1 year ago
5 0

The shaded portion area A corresponds to the area Ao of the outer circle minus the area Ai of the inner circle:

A = Ao - Ai

Also, the area of each circle of radius r is given by:

π r²

where the radius r is half the diameter d.

So, using r = d/2 in the above formula, we obtain:

π r² = π (d/2)² = (π/4) d²

Now, replacing each area with the corresponding diameter, we find:

A = Ao - Ai

= (π/4) 4² - (π/4) 1.5²

= (π/4) (4² - 1.5²)

= (π/4) (16 - 2.25)

= (π/4) (13.75)

≅ 10.799

Rounding the result to one decimal place, we find the answer:

10.8 m²

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Consider a set of one-dimensional points: 6, 12, 18, 24, 30, 42, 48.
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Answer:

1) With initial centroids 10-40, final clusters are

first cluster (6,12,18,24,30)

second cluster (42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 378

2) With initial centroids 10-20, final clusters are

first cluster (6,12,18,24)  

second cluster (30,42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 348

Step-by-step explanation:

K-means works as follows

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  • Then centroids are updated as the cluster means.
  • This process continues until clusters doesn't change anymore

1)  <u><em>initial centroids</em></u> 10-40

first cluster (6,12,18,24)  mean:15

second cluster (30,42,48) mean:40

<u><em>new centroids</em></u> 15-40

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

<u><em>final centroids</em></u> 18-45

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

Sum of Squared errors = (18-6)^{2}+(18-12)^{2}+(18-18)^{2}+(18-24)^{2}+(18-30)^{2}+(45-42)^{2}+(45-48)^{2}=378

2)<u><em>initial centroids</em></u> 10-20

first cluster (6,12)  mean:9

second cluster (18,24,30,42,48)  mean:32.4

<u><em>new centroids</em></u> 9-32.4

first cluster (6,12,18) mean:12

second cluster (24,30,42,48) mean:36

<u><em>new centroids</em></u> 12-36

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

<u><em>final centroids</em></u> 15-40

first cluster (6,12,18,24) mean:15  

second cluster (30,42,48) mean:40

Sum of Squared errors = (15-6)^{2}+(15-12)^{2}+(15-18)^{2}+(15-24)^{2}+(40-30)^{2}+(40-42)^{2}+(40-48)^{2}=348

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