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Molodets [167]
1 year ago
12

Question 31 (5 points) Find the area of the shaded portion if we know the outer circle has a diameter of 4 m and the inner circl

e has a diameter of 1.5 m. O O 10.8 m2 O 12.6 m2 O 43.2 m2 O 1.8 m2

Mathematics
1 answer:
Vadim26 [7]1 year ago
5 0

The shaded portion area A corresponds to the area Ao of the outer circle minus the area Ai of the inner circle:

A = Ao - Ai

Also, the area of each circle of radius r is given by:

π r²

where the radius r is half the diameter d.

So, using r = d/2 in the above formula, we obtain:

π r² = π (d/2)² = (π/4) d²

Now, replacing each area with the corresponding diameter, we find:

A = Ao - Ai

= (π/4) 4² - (π/4) 1.5²

= (π/4) (4² - 1.5²)

= (π/4) (16 - 2.25)

= (π/4) (13.75)

≅ 10.799

Rounding the result to one decimal place, we find the answer:

10.8 m²

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Answer:

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A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a
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P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=19, p=0.3)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(X \geq 5)

And we can use the complement rule:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

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