<h3>
Answer: (2, 3)</h3>
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Explanation:
1/4 = 0.25 is the scale factor
Multiply this with each coordinate of the given point
0.25*8 = 2 is the new x coordinate
0.25*12 = 3 is the new y coordinate
So (8,12) moves to (2,3) after applying the dilation
The scale factor k makes 0 < k < 1 true, so the point is closer to the origin after applying the dilation.
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Side note: this trick of multiplying the scale factor by each coordinate only works if the dilation is centered at the origin. For any other center, you'll need to apply a translation first, dilate, then translate back again.
Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
Answer: 41 1/4
Step-by-step explanation: 160/4=40
5/4= 1 1/4
LIKE IF CORRECT
I am inclined to think that it is A. or B. Because they represent the highest probability, if it is not those it might be D.
This probably didn’t help, but if it did. I am glad （╹◡╹）
