X+y^2=10
minus x from both sides
y^2=10-x
sub (10-x) for y^2 in other equation
Q=x(10-x)
Q=10x-x^2
now find the maximum value
take the derititive
dQ/dx=10-2x
it is zero at x=5
below that, it is positive
after 5, it is negative
max at x=5
solve for y
y^2=10-x
y^2=10-5
y^2=5
sqrt both sides
y=√5
x=5
y=√5
the max value is 25
Answer:
1/9 = 5/45 2/15 = 6/45
Step-by-step explanation:
9: 9, 18, 27, 36, 45
15: 15, 30, 45
3/8. Divide 3/4 by two to get 3/8.
Answer: 
<u>Step-by-step explanation:</u>
Answer:
4
Step-by-step explanation:
From the chioces give it would be 4
But it is actually 8
