Which equation represents a line that passes through (–2, 4) and has a slope of 2/5

Mathematics

2 answers:

labwork [276]2 years ago

6 0

Answer:

Step-by-step explanation:

y = 2/5x + p

We now that passes through (–2, 4)

2/5 × (-2) + p = 4

⇔ -4/5 + p = 4

⇔ p = 4 + 4/5

⇔ p = 20/5 + 4/5

⇔ p = 24/5

⇒ y = 2/5x + 24/5

cupoosta [38]2 years ago

3 0

Equation of a line is given by y - y1 = m(x - x1); where m is the slope.

y - 4 = 2/5 (x - (-2))

y - 4 = 2/5 (x + 2)

Hope this helps! :)

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Please help, I’ll mark your answer as brainliest!

statuscvo [17]

Answer:

$(x-230)^2+(y-220)^2=6100$

Step-by-step explanation:

The equation for a circle is $(x-h)^2+(y-k)^2=r^2$ , where $(h,k)$ is the vertex of the circle and $r$ is the radius. Immediately, since the center of the circle is given, we know what $h$ and $k$ are. $h$ is 230 and $k$ is 220.

The only thing we need to find is the radius, which will just be the distance from the center (230,220) to a point on the circumference (170,170). The distance between them can be calculated using the <u>distance formula</u>, which is really just the <u>Pythagorean Theorem</u> rearranged. The formula states that $d=\sqrt{x^2+y^2}$ , where $x$ is the change in the x-coordinates of the two points and $y$ is the change in the y-coordinates of the two points. Plug-in $x$ for 60 and $y$ for 50 to get $d=\sqrt{50^2+60^2}$ . Solve for $d$ , arriving at $\sqrt{6100}$ . Therefore, the radius of the circle is $\sqrt{6100}$ .