Answer:
A. y = –5x – 27
Step-by-step explanation:
Find the slope of the original line and use the point-slope formula y
−
y
1
=
m
(
x
−
x
1
) to find the line parallel to y
=
−
5
x
+
3
.
y
=
−
5
x
−
27 PARALLEL
...................................................................................................................................................
Find the negative reciprocal of the slope of the original line and use the point-slope formula y
−
y
1
=
m
(
x
−
x
1
) to find the line perpendicular to y
=
−
5
x
+
3
.
y
=
1
/5
x
+
21
/5 PERPENDICULAR
Yes i think it is reflection try reflection
Y = -10x + 1...slope here is -10. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal of a number, flip the number and change the sign. So our perpendicular line will need a slope of 1/10.
y = mx + b
slope(m) = 1/10
(5,7)....x = 5 and y = 7
now sub and find b, the y int
7 = 1/10(5) + b
7 = 1/2 + b
7 - 1/2 = b
14/2 - 1/2 = b
13/2 = b
so ur perpendicular line going thru (5,7) is y = 1/10x + 13/2
D because it would 44 below since 4 times 7 = 28 so it would switch over for to 6 times 7 =44
Answer:
x = 22
Step-by-step explanation:
∠VSR and ∠SRU are same- side interior angles and are supplementary, thus
5x + 4 + 44 + x = 180, that is
6x + 48 = 180 ( subtract 48 from both sides )
6x = 132 ( divide both sides by 6 )
x = 22
