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Diano4ka-milaya [45]
3 years ago
9

1. If Johnny had 5 apples, 2 carrots, 800 celery, 20 broccoli, and he gave away 2 apples, 1 carrot, 284 celery, and 12 broccoli,

how much stuff would he have left all together?
2. Nemo the fish hated Marlin the fish and Dory the fish. He snapped Marlin's neck. Dory tickled Nemo's back and he had a stroke. Nemo is dead. How many fish are left?

3. Tony gasped. How many times did Tony gasp?

4. Mark decided to buy 100 Christmas gifts exactly. If he had 4 children, how many gifts would he split between them?

5. Kermit the Frog has 12 dead bodies. The dead bodies include: Spongebob, Patrick, Elmo, Big Bird, Nemo, Marlin, Ms. Piggy, Peppa Pig, George Pig, Sonic the Hedgehog, and Mr. Krabs. Peppa Pig, Nemo, Patrick, and Sonic the Hedgehog came back alive. Patrick ran into a wall and died while they tried to escape. How many dead bodies does Kermit the Frog have now?
Mathematics
1 answer:
Nostrana [21]3 years ago
4 0

Answer:25

you would have to divided 100 divided by 4 wich equals 25.

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In a school of 685 students, there are 385 students involved in sports teams, and there are
svet-max [94.6K]

Answer:

A) check attached picture

B) 272

C) 0.4478

Step-by-step explanation:

From the information given ;

A) The Venn diagram of the information can be found in the attached picture.

B) Number of students involved in both team sports and music.

n(student in sports team) = 385

n(students involved in music) = 450

Number of students involved in both music and team sport = y

Number of students not involved in either team sport or music = 87

Total number of students = 650

Therefore,

n(music alone) = 450 - y

n(team sport alone) = 385 - y

Adding the following:

n(music alone) + n(team sport alone) + n( both music and team sport) + n(neither music nor team sport) = Total number of students

450 - y + 385 - y + y + 87 = 650

922 - y = 650

922 - 650 = y

y = 272

Therefore, number of students involved in both music and team sport = 272

C) probability of being involved in team sport or in music.

P(being involved in music) = (450 - 272) / 650 = 0.2738

P(being involved in team sport) = (385 - 272) / 650 = 0.1738

P(involved in both) = 272 / 650 = 0.4184

P(involved in neither) = 87 / 650 = 0.1338

P(being involved in team sport) or p(being involved in music)

P(being involved in team sport) + p(being involved in music)

0.1738 + 0.2738 = 0.4478

3 0
3 years ago
What is 75percent of 200​
Setler79 [48]

Answer:

150

Step-by-step explanation:

4 0
2 years ago
Factor the expression. -20x + 32
fgiga [73]
Factor -20x+32
which comes out to 4(-5x+8)
answer: 4(-5x+8)
hope this helped :)
8 0
3 years ago
If you borrow $100 at 50% interest, how much interest do you think you will have to pay?
Elena L [17]

Answer:

the answer is 50 dollars

Step-by-step explanation:

because your interest is only 50% so whats 100 divided into 2 its 50

6 0
3 years ago
Read 2 more answers
Is matrix multiplication comutative?
konstantin123 [22]

Answer:

Matrix multiplication is not conmutative

Step-by-step explanation:

The matrix multiplication can be performed if the number of columns of the first matrix is equal to the number of rows of the second matrix

Let A with dimension mxn and B with dimension nxp represent two matrix

The multiplication of A by B is a matrix C with dimension mxp, but the multiplication of B by A is can't be calculated because the number of columns of B is not the number of rows of A. Therefore, you can notice that is not conmutative in general.

But even if the multiplication of AB and BA is defined (For example if A and B are squared matrix of 2x2) the multiplication is not necessary conmutative.

The matrix multiplication result is a matrix which entries are given by dot product of the corresponding row of the first matrix and the corresponding column of the second matrix:

A=\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\\B= \left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\\AB = \left[\begin{array}{ccc}a11b11+a12b21&a11b12+a12b22\\a21b11+a22b21&a21b12+a22b22\end{array}\right]\\\\BA=\left[\begin{array}{ccc}b11a11+b12a21&b11a12+b12a22\\b21a11+b22ba21&b21a12+b22a22\end{array}\right]

Notice that in general, the result is not the same. It could be the same for very specific values of the elements of each matrix.

6 0
3 years ago
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