Answer:
The equation is always false
Step-by-step explanation:
Answer:
3. ∠BDE ≅ ∠BAC; Corresponding Angles Postulate 5. ΔBDE ~ ΔBAC; Angle-Angle (AA) Similarity Postulate
Step-by-step explanation:
3) Statement ∠BDE ≅ ∠BAC;
Corresponding Angles Postulate
The Corresponding Angles Postulate states that given two parallel lines, in this case DE and AC cut by a transversal one (AB) than these corresponding angles are congruent.
5) ΔBDE ~ ΔBAC; Angle-Angle (AA) Similarity Postulate
If two pairs of corresponding angles are congruent (∠D and ∠A, ∠E and ∠C) than these triangles are similar.
*Not 100% sure what you want but here goes*
Step-by-step explanation:
So what you do is create a table for this example label the x values say -2 through 2. Then you plug in the x value to the equation so for 2 its <u>y=</u><u> </u><u>2</u><u>(</u><u>2</u><u>)</u><u>+</u><u>5</u> which is 9. Continue this for the rest of the graph and that should do it.
Hope this helps
Answer:
No Solution.
Step-by-step explanation:
2(x-1)-y=-8
y=2x+8
----------------
2x-2-(2x+8)=-8
2x-2-2x-8=-8
2x-2x-2-8=-8
0-2-8=-8
-2-8=-8
-10=-8
no solution