The answer your looking for is y < - 2IxI
Answer:
The proportion of trees greater than 5 inches is expected to be 0.25 of the total amount of trees.
Step-by-step explanation:
In this problem we have a normal ditribution with mean of 4.0 in and standard deviation of 1.5 in.
The proportion of the trees that are expected to have diameters greater than 5 inches is equal to the probability of having a tree greater than 5 inches.
We can calculate the z value for x=5 in and then look up in a standard normal distribution table the probability of z.
The proportion of trees greater than 5 inches is expected to be 0.25 of the total amount of trees.
<span>System 1 and system 2, because the second equation in system 2 is obtained by adding the first equation in system 1 to two times the second equation in system 1
This is the correct answer because not only is it true but it also follows the property of solving systems of equations with adding the equations. To prove that it is true:
2nd equation in system #2 = 1st equation in system #1 + 2(2nd equation in system #1)
</span>10x − 7y = 18 == 4x − 5y = 2 + 2(<span>3x − y = 8)
10x - 7y = 18 == 4x - 5y = 2 + 6x - 2y = 16
10x = 7y = 18 == 10x - 7y = 18</span>
= 3 × 10-11
(scientific notation)
= 3e-11
(scientific e notation)
= 30 × 10-^12
(engineering notation)
(trillionth; prefix pico- (p))
= 0.0000000000
<span>(real number)</span>
