Answer:
Step-by-step explanation:
If the center of the circle is (1,-2) and the circle passes through the point (4,2), then the radius of the circle is
The equation of the circle with center and radius r is
In your case, the equation is
Help me please thanks
2 answers:
You might be interested in
Answer: The point where the two graphed lines cross is the solution to the system of equations. (1, -1)
Step-by-step explanation:
The second equation is already in slope-intercept form y = x - 2
the slope is +1 (invisible coefficient of x) and the y-intercept is -2
y = mx +b
"m" is the slope (the coefficient of x) Positive slopes go up from left to right
"b" is the y-intercept, where the graphed line crosses the x-axis
Rewrite the first equation in slope-intercept form.
6x + y = 5 subtract 6x from both sides
<em>-6x</em> + 6x +y = -<em>6x</em> + 5 .( left side 6x + 6x =0 so "cancel")
y = -6x + 5
Then you know the slope and the intercepts
b = 5 so start with a point at +5 in the y-axis
m = -6 so from there go down 6 and over to the right 1 square and plot another point. Draw a straight line through the two points.
The point where the two graphed lines cross is the solution to the system of equations.
Your graph should look like the screenshot below.
