3 years ago

Calculate the angular momentum of a particle of mass m moving with constant velocity v about origin o.

Mathematics

1 answer:

Ymorist [56]3 years ago

5 0

The formula for this ( horizontal circular orbit with the origin at the center) is
L = mvr

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Explain how to solve 2^x + 1 = 9 using the change of base formula log base b of y equals log y over log b. Include the solution

elena55 [62]

Answer:

$x=2.170$

Step-by-step explanation:

The given equation is $2^{x+1}=9$ .

We take logarithm of both sides to base 2 to get:

$\log_2(2^{x+1})=\log_29$

Apply the power rule of logarithms to get:

$x+1=\log_29$

We now apply the change of base formula:

$x+1=\frac{\log_{10}9}{\log_{10}2}$

$x+1=\frac{0.9542}{0.3010}$

$x+1=3.1701$

$x=3.1701-1$

$x=2.1701$

To the nearest thousandth, $x=2.170$

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Step-by-step explanation:

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Maksim231197 [3]

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(1,3)....x2 = 1 and y2 = 3

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