3. Determine if the following triangle is a right triangle or not using the Pythagorean Theorem Converse. Triangle with side len
1 answer:
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All we do to figure this question out is by graphing and connect the dots! Now that we can see what the figure looks like. We can tell that the figure IS a right triangle.
m-perpendicular: -1/2
point slope = 2x - 2
m-perpendicular: -1/2
point slope = 2x - 2
Answer:
(x-12)(x+12) and (2a+b)(x-3y)
Step-by-step explanation:
So first we have:
x^2-144
The key here is that there is no bx in the ax^2+bx+c equation here.
This means that b must equal 0, or in other words, cancel itself out.
To do this, first, the two factors must have opposite signs, and secondly, the blank values must be equal (x+_) * (x-_)
What could they be? The c value, 144, equals the two blank values multiplied together. Since they are in the same in this case, blank value^2 = 144, or
So the answer is:
(x+12)(x-12)
Next we have:
2ax - 6ay + bx - 3by
This is a bit more tricky, but first we must facor out some numbers/variables to simplify.
Lets seperate the two parts of this equation:
2ax - 6ay and bx - 3by
Now lets look at:
2ax - 6ay
How can we simplify this? Factor the 2a, which both have in common:
2a(x-3y)
Now lets look at and factor it too:
bx - 3by
Only b can be factored out, which gives us:
b(x-3y)
Now lets put this back into our orginal equation:
2a(x-3y) + b(x-3y)
Both of these have x-3y. Concidence? Nope!
From the way we split the equation into two pieces and factored, the two x-3ys are actually the same, and we can combine them!
Then, the 2a and the +b can be combined to give us:
(2a+b)
Puttting these together gives us:
(2a+b)(x-3y)
Hope this helps!