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densk [106]
2 years ago
10

A ride-sharing company charges $6 per mile plus a $10 surcharge during peak hours. Suppose Manish’s ride during peak hours costs

$22. To determine how many miles he traveled during this ride, solve for x in the following equation: 6x + 10 = 22
Mathematics
1 answer:
nadya68 [22]2 years ago
7 0

Answer:

2 miles

Step-by-step explanation:

6X + 10 = 22

X = (22-10)/6 = 12/6 = 2 miles

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Jackie has 1/3 of a Hershey bar.steven has 4/12 of a Hershey bar.How much do they have together?
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Since Jackie has 1/3 and Steven has 4/12 we add them together


4/12+1/3= 2/3

Together they have 2/3 of a Hershey Bar
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3 years ago
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What is the perimeter of the truss in feet?
Zanzabum

I think the truss is just one of those triangles whose sides are 3ft, 3ft, 3ft so its perimeter is


Answer: 9 feet



5 0
3 years ago
Consider the following graph of two functions,S(1) + 8(2)Step 1 of 2: Finds (1) + 8(2)Enable Zoom/Pan8(x) = x2 - 2x - 1S(x) = -x
kumpel [21]

.Given:

\begin{gathered} f(x)=-x+1 \\ g(x)=x^2-2x-1 \end{gathered}

ToDetermine: The value of

f(1)+g(2)

Solution

\begin{gathered} f(x)=-x+1 \\ f(1)=-1+1 \\ f(1)=0 \end{gathered}\begin{gathered} g(x)=x^2-2x-1 \\ g(2)=(2)^2-2(2)-1 \\ g(2)=4-4-1 \\ g(2)=-1 \\ f(1)+g(2)=0+(-1) \\ f(1)+g(2)=-1 \end{gathered}

Hence, f(1) + g(2) = -1

3 0
1 year ago
What is the value of the 8th term of the sequence 4, 8, 16, 32, ...?
vladimir1956 [14]

Answer:

512

Step-by-step explanation:

The sequence is doing the number times 2, so 4 times 2 equals 8,

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If you do this enough, you will get 512 as the 8th term.

3 0
2 years ago
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A computer chess game and a human chess champion are evenly matched. They play twelve games. Find probabilities for the followin
sleet_krkn [62]

Answer:

The probability that they each win six games is 0.225.      

Step-by-step explanation:

Given : A computer chess game and a human chess champion are evenly matched. They play twelve games.

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Solution :

Applying binomial distribution,

Here n=12 and p=0.5

P(X=k)=\frac{n!}{k!(n-k)!}\times p^k\times (1-p)^{n-k}

The probability that they each win six games is k=6.

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P(X=6)=11\times 2\times 3\times 2\times 7\times 0.015625\times 0.015625

P(X=6)=0.225

Therefore, The probability that they each win six games is 0.225.

3 0
3 years ago
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